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siniylev [52]
2 years ago
5

As soon as possible please.

Mathematics
1 answer:
eduard2 years ago
7 0

Answer:

x = - 7

Step-by-step explanation:

Express the diagrams in equation form with output y

A y = 5x - 4

B y = 3x + 8

Equate the right sides so that A is 3 times B

5x - 4 = 3(3x + 8) ← distribute parenthesis

5x - 4 = 9x + 24 ( subtract 9x from both sides )

- 4x - 4 = 24 ( add 4 to both sides )

- 4x = 28 ( divide both sides by - 4 )

x = - 7

As a check

A  y = 5(- 7) - 4 = - 35 - 4 = - 39

B  y = 3(- 7) + 8 = - 21 + 8 = - 13

then - 13 × 3 = - 39

The required input is x = - 7

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Factor each.<br><br><br> Please help!
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Answer:

1) The factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) The factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

Step-by-step explanation:

1) Factor : x^2-3x+2=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

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We can break them as (-2x)( -x)

Solving:

x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0

So, factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) Factor: x^2+2x-8=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

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We can break them as (4x)( -2x)

Solving

x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0

So, factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

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