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2 years ago

Factor k2+7k+10 PLEASE HELP

Mathematics

1 answer:

Elanso [62]2 years ago

4 0

Answer:

(k + 5) (k + 2)

Step-by-step explanation:

k² + 7k + 10

k² + 2k + 5k + 10

k(k + 2) + 5(k + 2)

(k + 5) (k + 2)

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Of F(x) and

Musya8 [376]

Do u mean what is f(8)?

(X) = 2x + 5
Inverse = (x-5)/2

F(x) = (x-5)/2
F(8) = (8-5)/2
= 3/2 = 1.5

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4 years ago

Evaluate each expression. <br> 18^-4 x 6^7

rosijanka [135]

Answer:

8/3

Step-by-step explanation:

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4 years ago

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36 out of 100 randomly selected taxpayers knew about tax incentives for installing energy-saving furnaces. Find a 90% confidence

tresset_1 [31]

Answer:

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 100, \pi = \frac{36}{60} = 0.6$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.28$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.44$

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

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4 years ago

What percent of 56 is 19.6

blsea [12.9K]

The answer would be 10.976.

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4 years ago

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8÷2(2+2)<br><br> is it 1 or 16...

Vedmedyk [2.9K]

nevermind about my answer then oops

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4 years ago

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