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stepan [7]
2 years ago
14

​ 7x+63= What is the answer?

Mathematics
1 answer:
NARA [144]2 years ago
8 0
Answer: x=9

Explanation:

Take the binomial and divide it by the number in front of the variable. 63/7=9
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abruzzese [7]
The answer for the problems are below in the picture let me know if that makes sense.

5 0
3 years ago
Point D is on segment BC. Segment BC measures 8x
Kay [80]

Answer:

DB = 82

Step-by-step explanation:

3x + 8 + 4x + 10 = 8x

7x + 18 = 8x

18 = 8x - 7x

18 = x

----------------------------------------

DB: 4x + 10

4 (18) + 10 = 82

4 0
3 years ago
How tto sollve the quadratic equation of r2=96
maksim [4K]
r^2 =96 \\ r=б \sqrt{96}  \\ r=б4 \sqrt{6}

Answer: r=-4√6,  r=4√6
4 0
4 years ago
Read 2 more answers
Use the points A(4, 4) and B(4, −5). Complete the description of segment AB and find its length.
Svet_ta [14]

Use the points A(4, 4) and B(4, −5)

(1) (a) From two points , we will get a vertical line when 'x' values are same and horizontal line segment when 'y' values are same

Here in A(4, 4) and B(4, −5) , the x values are same so the segment AB is a Vertical . The length is the difference between y values ( 4 -(-5)) = 9

Segment AB is a Vertical segment that is 9 units long.

(2) Describe the image of segment AB under the transformation

(x, y) ----> (x, 2y)

A(4, 4) -----> (4, 8)

and B(4, −5) ---> (4, -10)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 8 -(-10)) = 18

The image of segment AB is a Vertical segment that is 18 units long.

(3) Describe the image of segment AB under the transformation

(x, y) ----> (x + 2, y)

A(4, 4) -----> (6, 4)

and B(4, −5) ---> (6, -5)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 4 -(-5)) = 9

The image of AB is a Vertical segment 2 units to the right of the original segment that is 9 units long.

8 0
3 years ago
Suppose that R(x) is a polynomial of degree 13 whose coefficients are real numbers. also, suppose that R(x) has the following ze
postnew [5]

(a) Complex zeros of a polynomial come in pairs.

If a + bi is a zero of a polynomial then its conjugate a - bi is also a zero of the polynomial.

The given complex zeros of R(x) are 1 + 3i and -2i.

1 - 3i is the conjugate of 1 + 3i.

Hence, another zero of R(x) is 1 - 3i

b)

Since the polynomial R(x) is of order 13 then R(x) must have 13 zeros.

The given complex zeros of R(x) are 1 + 3i and -2i. We also know that the conjugates of 1 + 3i and -2i are zeros of R(x). Hence, R(x) has at least 4 complex roots

Hence, the maximum number of real zeros of R(x) is (13 -4).

The maximum number of real zeros of R(x) is 9

c) Let the maximum number of nonreal zeros (complex roots) be n

Complex roots come in pairs. Therefore, n must be even.

Hence, n ≤ 13 - 1 = 12

n ≤ 10

We have been given a real zero of R(x), 3 ( With the multiplicity of 4).

12 - 4 = 8

Therefore,

n ≤ 8.

Hence the maximum number of nonreal zeros of R(x) is 8

3 0
1 year ago
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