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notsponge [240]
2 years ago
12

Kinda confused on this question.

Mathematics
1 answer:
salantis [7]2 years ago
6 0
6x+5= 9x-4
9=3x
3=x
To find RS you need to substitute x back into the equation
9(3)-4
27-4
23

23 is the answer
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Which expressions are equivalent to 4x^4-9x^2?
weeeeeb [17]
We can cosider this to be  a difference of 2 squares  so 

4x^4 - 9x^2 = (2x^2 - 3x)(2x^2 + 3x)   so D is one answer

also we could take x^2  out and get 
x^2(4x^2 - 9)  = C
3 0
3 years ago
What is the solution to the equation 6 x + 2 = 9 x minus 1?
lina2011 [118]

Answer:

x=1

Step-by-step explanation:

By substituting 1 into the equation for x, both sides will equal 8.

4 0
3 years ago
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miskamm [114]

Answer:

The volume of the rectangular prism should be 4.096.

6 0
2 years ago
Read 2 more answers
In a widget factory, machines A, B, and C manufacture, respectively, 20, 30, and 50 percent of the total. Of their output 6, 3,
steposvetlana [31]

Answer:

38.71% probability it was manufactured by machine A.

29.03% probability it was manufactured by machine B.

32.26% probability it was manufactured by machine C.

Step-by-step explanation:

We have these following probabilities:

A 20% probability that the chip was fabricated by machine A.

A 30% probability that the chip was fabricated by machine B.

A 50% probability that the chip was fabricated by machine C.

A 6% probability that a chip fabricated by machine A was defective.

A 3% probability that a chip fabricated by machine B was defective.

A 2% probability that a chip fabricated by machine C was defective.

The question can be formulated as:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What are the probabilities that it was manufactured by machines A, B, and C?

Machine A

What is the probability that the widget was manufactures by machine A, given that it is defective?

P(B) is the probability that it was manufactures by machine A. So P(B) = 0.20

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So P(A/B) = 0.06

P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.2*0.06}{0.031} = 0.3871

38.71% probability it was manufactured by machine A.

Machine B

What is the probability that the widget was manufactures by machine B, given that it is defective?

P(B) is the probability that it was manufactures by machine B. So P(B) = 0.30

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So P(A/B) = 0.03

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.03}{0.031} = 0.2903

29.03% probability it was manufactured by machine B.

Machine C

What is the probability that the widget was manufactures by machine C, given that it is defective?

P(B) is the probability that it was manufactures by machine C. So P(B) = 0.50

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So P(A/B) = 0.02

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.02}{0.031} = 0.3226

32.26% probability it was manufactured by machine C.

6 0
3 years ago
Complete the proof by filling in the missing reasons using the Reasoning bank.
Nezavi [6.7K]

 Statements                                                      Reasons

1. M lies on AB                                                    Given

2. AM+MB=AB                                                   Definition of midpoint

3. 2x+2+4x-4 = 16                                             Segment Addition Postulate

4. 6x-2 = 16                                                         Combining like terms

5. 6x = 18                                                             Addition Property of equality

6. x = 3                                                               Division Property of equality

7. AM=2(3)+2 and MB=4(3)-4                            Substitution property of equality

8. AM=8 and MB=8                                              Definition of midpoint

9. M is a midpoint                                                Hence, proved.

3 0
3 years ago
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