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blondinia [14]
2 years ago
13

The volume of a gas at 7. 00°c is 49. 0 ml. If the volume increases to 74. 0 ml and the pressure is constant, what will the temp

erature of the gas be?.
SAT
1 answer:
Nadusha1986 [10]2 years ago
8 0

Answer:

150°C

Explanation:

T1 = 7.00 C = 7 + 273 = 280 K

V1 = 49.0 ml

V2 = 74.0 ml

T2 = ?

Under constant pressure, V1/T1 = V2/T2, so

T2 = T1 * (V2/V1) = 280 * (74/49) = 423 K = (423 - 273) C = 150 C

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3 years ago
What is the ph of a 0. 300 m solution of aniline (c₆h₅nh₂, kb = 4. 3 × 10⁻¹⁰)?.
yawa3891 [41]

The pH of the solution of aniline is; pH = 4.64

<h3>pH of aniline solution</h3>

According to the question;

  • We are required to determine the hydrogen ion concentration, pH of the given aniline solution.

Since, the given Kb is kb = 4. 3 × 10⁻¹⁰.

Hence, it follows that;

  • Ka = 10-¹⁴/4. 3 × 10⁻¹⁰.

  • Ka = 2.3 × 10⁻⁵.

On this note, the pH of aniline solution is;

  • pH = -log {2.3 × 10⁻⁵}

pH = 4.64.

Ultimately, the pH of the aniline solution given is; 4.64

Read more on pH of solutions;

brainly.com/question/25639733

3 0
2 years ago
A child riding a bicycle at 15 m/s accelerates at 3. 0 m/s/s for 4. 0 s. What is the child's speed at the end of this 4. 0 s int
mamaluj [8]

Answer:

The final speed of bicycle would be <u>27 m/s</u>².

Step-by-step explanation:

<u>Given</u> :

  • \small\red\bull Initial velocity (u) = 15 m/s
  • \small\red\bull Acceleration (a) = 3.0 m/s²
  • \small\red\bull Time = 4 seconds

<u>To</u><u> </u><u>Find</u> :

  • \small\red\bull Final velocity (v)

<u>Using</u><u> </u><u>Formula</u> :

\longrightarrow{\pmb{\sf{v = u + at}}}

  • \small\blue\star v = final velocity
  • \small\blue\star u = initial velocity
  • \small\blue\star a = acceleration
  • \small\blue\star t = time taken

<u>Solution</u> :

Substituting the values in the formula to find the final velocity :

\longrightarrow{\sf{v = u + at}}

\longrightarrow{\sf{v = 15 + (3.0 \times 4)}}

\longrightarrow{\sf{v = 15 + (3 \times 4)}}

\longrightarrow{\sf{v = 15 +(12)}}

\longrightarrow{\sf{v = 15 +12}}

\longrightarrow{\sf{v = 27 \:  {m/s}^{2}}}

\star{\underline{\boxed{\red{\sf{v = 27 \:  {m/s}^{2}}}}}}

Hence, the final speed of bicycle would be 27 m/s².

\rule{300}{1.5}

3 0
3 years ago
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