Answer:
Color : ___Green __yellow ___purple __ Grey
Prob : ____0.30 ___0.10 ______ 0.35 ___ 0.25
4 pins
Step-by-step explanation:
Color : ___Green __yellow ___purple __ Grey
Prob : ___. _______________ 0.35 ___ 0.25
P(green) = 3 * P(yellow)
ΣP = 1
Let
P(yellow) = x
P(green) = 3x
Hence,
x + 3x + 0.35 + 0.25 = 1
4x + 0.60 = 1
4x = 1 - 0.60
4x = 0.40
x = 0.4 / 4
x = 0.1
Hence,
P(yellow) = 0.1
P(green) = 0.1 * 3 = 0.3
Color : ___Green __yellow ___purple __ Grey
Prob : ____0.30 ___0.10 ______ 0.35 ___ 0.25
B)
If there are 14 pins in bag :
Number of green pins :
X * p(x)
14 * 0.3
= 4.2
= 4 pins
Answer:
Step-by-step explanation:
ans is in the attachment.
Answer:
-5 ; 1/2
Step-by-step explanation:
<u>GIVEN :-</u>
- A quadratic polynomial f(x) = 2x² + 9x - 5
<u>TO FIND :-</u>
- Zeroes of f(x) = 2x² + 9x - 5
<u>GENERAL CONCEPTS TO BE USED IN THIS QUESTION :-</u>
Lets say there's a quadratic polynomial f(x) = ax² + bx + c , whose factors are (x - α) & (x - β). To find the values of x for which f(x) will be zero , equate the factors of f(x) with 0.
⇒ (x - α) = 0 & (x - β) = 0
⇒ x = α & x = β
Hence, it can be concluded that if (x - α) & (x - β) are factors of f(x) , then α & β are the roots of f(x).
<u>SOLUTION :-</u>
Factorise f(x) = 2x² + 9x - 5.
- Take '2x' common from first two terms & '-1' from last two terms.
- Take (x + 5) common from the whole expression.
So , the factors of f(x) are (x + 5) & (2x - 1). Now equate the factors with zero.
⇒ (x + 5) = 0 & (2x - 1) = 0
⇒ x = -5 & x = 1/2
∴ The zeroes of f(x) = 2x² + 9x - 5 are (-5) & (1/2)
<u>VERIFICATION :-</u>
1) Put x = -5 in f(x) = 2x² + 9x - 5
⇒ f(-5) = 2(-5)² + 9×(-5) - 5
= 50 - 45 - 5
= 50 - 50
= 0
2) Put x = 1/2 in f(x) = 2x² + 9x - 5
Answer:
X=-2 or x=-7
Step-by-step explanation:
(x+2)(x+7)=0
X=-2 or x=-7
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