No he did not that was a poor choice.
#include
#include
using namespace std;
int main(){
int input[] = {-19, 34, -54, 65, -1};
std::vector voutput:
std::vector vinput (input, input + sizeof(input) / sizeof(int) );
for (std::vector::iterator it = vinput.begin(); it != vinput.end(); ++it)
if(*it > 0) voutput.insert(voutput.begin(), *it);
for(std::vector::iterator it = voutput.begin(); it < voutput.end(); ++it)
std::cout << *it << ‘\n’ ;
return 0;
}
Answer:
I think it would be.
A-Metal-cast pouring system
<h2>
I hope it helps</h2>
Answer:
DHCP reservation is the correct answer.
Explanation:
It is the Internet Protocol assignment which is not temporary. It is the particular address of the Internet Protocol within a DHCP set, which is not temporarily assigned to a particular DHCP client for lease use.
So, the device of the last user required the address of the Internet Protocol whenever they linked to the company's server. The following reservation provides the permission to use static addresses of the Internet Protocol without affecting the company's server.
