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svetoff [14.1K]
2 years ago
12

WILL GIVE BRAINLIEST A set of numbers is shown:

Mathematics
1 answer:
ad-work [718]2 years ago
4 0

10 and 15 dear^^ 5(15) + 3(15) =28

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Simplify the following expression <br> 1<br> - (24-16c)<br> 4
raketka [301]

Answer:

-24 + 16c

Step-by-step explanation:

There are a couple things we need to know here:

  1. We need to know how to distribute a negative
  2. We need to know that we cannot combine 24 and -16c, because we can only combine like terms (we can only combine terms that don't have a c with other terms that don't have a c).

To help distribute a negative, we can first write the problem like this:

-1 * (24 - 16c)

So all we're doing is multiplying -1 by 24 and by -16c, which will get us:

-24 + 16c, which is the answer.

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4 years ago
What is 1.086 rounded to the nearest whole number
Sphinxa [80]
1.086 rounded to the nearest whole number is 1
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3 years ago
Finding area and perimeter for each shape
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Answer: first one is 15.01

Step-by-step explanation:

7 0
4 years ago
A blueprint of an office shows the bottom edge of the roof to be 54 feet above the ground. If the roof rises to a
frez [133]

Answer:

It is 4

Step-by-step explanation:

6 0
3 years ago
A college is creating a new rectangular parking lot. the length is 0.17 mile longer than the width and the area of the parking l
Svetradugi [14.3K]
Let's call the width of the parking lot w.
The length of the parking lot if .17 more than the width so the length is w + .17

The parking lot is rectangular so its area is found by multiplying the length and the width. That is, the area is equal to what we obtain when we multiply w by w+.17. The area is: A = w(w+.17)= w^{2} +.17w

We are also told that the area is equal to .039 square miles so we set the expression we obtained for the area equal to .039 as follows.

w^{2} +.17w=.039

Since w represents the width of the rectangular lot, we can solve this equation for w to find the width. This is a quadratic equation (the highest exponent of the variable w is 2). We solve these by setting them equal to zero and then using the quadratic formula.

Setting our equation equal to zero (subtract .039 from both sides) gives us:
w^{2} +.17w-.039=0

The quadratic formula is as follows. Since the equation is in terms of w we write it as "w = ..." instead of the usual "x = ..."

w= \frac{-bplusminus \sqrt{ b^{2} -4ac} }{2a}

The part I write as "plusminus" is typically written with a + sign over a - sign. For right now let's leave it at that. Later in the problem we will see what it means and what to do with it.

To use the formula we have to identify a, b and c.

a is the coefficient of the squared term. That is, the number in front of w^{2} which here is 1.

b is the coefficient of the linear term. That is, the number in front of w which here is .17

c is the constant (the number by itself0 which is -.039

So we have:
a=1
b=.17
c=-.039

We plug these into the quadratic formula to obtain:
w= \frac{-.17plusminus \sqrt{ .17^{2} -(4)(1)(-.039)} }{(2)(1)}
w= \frac{-.17plusminus \sqrt{ .0289+.156} }{2}
w= \frac{-.17plusminus \sqrt{ .189} }{2}
w= \frac{-.17plusminus.43} {2}

Here is where the "pluminus" comes in. We continue to simplify the expression on the right but we split it in two. In one case we use "plus" and in the other "minus". That is, we add in one and subtract in the other. This gives us:
w= \frac{-.17+.43}{2}= \frac{.26}{2}=.13
and
w= \frac{-.17-.43}{2}= \frac{-.6}{2}=-.3

w is the width of the rectangular lot so it is a distance and cannot be measured using negative numbers. The width of the rectangular must be positive so we disregard the negative answer.

The width of the rectangle is .13 miles

Recall that the length of the rectangle is .17 more than the width. That is, the length is w+.17 and as we know the width to be .13 miles the length is .13 + .17 = .3 miles

The answer therefore is:
width = .13 miles
length = .3


4 0
3 years ago
Read 2 more answers
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