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igomit [66]
2 years ago
7

If two triangles have three congruent, corresponding

Mathematics
1 answer:
Tcecarenko [31]2 years ago
5 0

Answer:

  a pair of corresponding sides must be shown congruent

Step-by-step explanation:

The triangles are "similar" if corresponding angles are congruent. The triangles will only be "congruent" if corresponding sides are also congruent. The additional information needed is that <em>there is one congruent pair of corresponding sides</em>. (If there's one pair, all pairs of corresponding sides will be congruent.)

Having one pair of corresponding sides congruent would allow you to invoke either of the ASA or AAS congruence postulates.

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Cerrena [4.2K]
It might be 2.5 but I could be wrong
3 0
2 years ago
Solve for me. 6= (y+2)
Rama09 [41]

Answer:

y=4

Step-by-step explanation:

if y+2=6, you can subtract 2 from both sides, giving you y=6-2. 6-2=4, which is y.

6 0
3 years ago
Read 2 more answers
42 more than half a number is the same as four times the number. What is the number?
Dmitry_Shevchenko [17]



1/2x + 42 = 4x
-1/2x           -1/2x
------------------------
42 = 3.5x
/3.5   /3.5
------------------------
12 = x
the number is 12


explanation: 42 more than 1/2 of a number can be written as 1/2x + 42
four times a number can be written as 4x.
42 more than 1/2 of a number is equal to 4 times a number. So 1/2x + 42 = 4x.

Hope this helps :)
8 0
3 years ago
What is the radius of a circle with a sector area of 7 sq. ft. and an arc whose measure is 70°?
Radda [10]
<span>the radius is </span>6 feet.
5 0
3 years ago
Read 2 more answers
In Seaton Park school, 60% of the boys play baseball and 24% of the boys play baseball and football. What percentage of those th
Dmitrij [34]

Answer:

0.4\%

Step-by-step explanation:

Given: 60% of the boys play baseball and 24% of the boys play baseball and football in Seaton Park School

To find: percentage of those that play baseball also play football

Solution:

Let B denotes boys who play baseball and F denotes boys who play football.

P(B)=60\%

P(F\cap B)=24\%

Percentage of those that play baseball also play football = P\left ( F|B \right )=\frac{P(F\cap B)}{P(B)}=\frac{24}{60}=\frac{2}{5}=0.4\%

7 0
3 years ago
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