May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
The word you're looking for is "differentiate", not "derive".
The relationship between square units is, area is measured in square units. Plus, square units are in an area sometimes.
Answer:
B
Step-by-step explanation:
I think is b.....Hope this helps byeee.
Answer:
post the graph
Step-by-step explanation:
could you post the graph so i could help yoi
