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2 years ago

14

Given the lengths of two sides of a triangle, write an inequality to indicate between which two numbers the length of the third

side must fall. 22 and 15.

1 answer:

CaHeK987 [17]2 years ago

5 0

Answer:

1. 5 <3rd side<21 2. 12.1<3rd side<35.1

Step-by-step explanation:

;-)

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Drag the measurements to put them in order From least to greatest 7 g 7 kg seven centigrams 7 mg

Arturiano [62]

Answer:

7 mg, 7 centigrams, 7g, 7kg

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3 years ago

Given the function f(x) = 3|x – 2| + 6, for what values of x is f(x) = 18?

Radda [10]

C
..............................

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3 years ago

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No clue how to do this.

tatiyna

Answer:

Look at the graph, on the left side it says snow on the ground, and it starts on 5, as the storm continued more fell. nvm.

Step-by-step explanation: The answer to your question is 5, because that is how much is on the ground at the beggining.

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3 years ago

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During a tunnel construction project, engineers used explosives to excavate partway into a mountain. Because of time constraints

AnnyKZ [126]

The given data can be tabulated as:

number of days,x length of tunnel (ft), y

0 225

5 350

20 725

30 975

55 1,600

To check if the growth is linear, the slope at points (0, 225) and (5, 350), and (0, 225) and (20, 725) should be equal. The formula for slope is:

m = (y2 – y1) / (x2 – x1)

Finding for slope (0, 225) and (5, 350):

m = (350 – 225) / (5 – 0) = 25

Finding for slope (0, 225) and (20, 725):

m = (725 – 225) / (20 – 0) = 25

Therefore the equation is linear in the form of:

y = mx + b

where b is the value of y at x = 0, so b = 225

The complete equation is:

y = 25x + 225

At x = 86 days

y = 25(86) + 225

y = 2,375 ft

Therefore the length of the completed tunnel is 2,375 feet.

5 0

3 years ago

Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)

Fantom [35]

Answer:

Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .

Hence, $\tan(x)$ would be:

$\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}$ .

7 0

2 years ago