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2 years ago

4x^2-11x=78 quadratic formula

1 answer:

7 0

Answer: x=6, -13/4

Explanation: Solve the equation for x by finding a, b, and cod the quadratic then applying the quadratic formula

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Please help!

Vilka [71]

Answer:

The number of comic books did they have in all = 56

Step-by-step explanation:

The ratio of comics with Susan : Abe = 3 : 5

Let us assume the common factor on this ratio = m

So, the number of comics Susan has = 3 m

The number of comics Abe has = 5 m

Also, given: Abe had 14 more comic books than Susan

So, the number of comics Abe had = 14 + 3 m

⇒ 5 m = 3 m + 14

or, 2 m = 14, or m = 7

So, the number of books Susan has = 3 m = 3 x 7 = 21 books

The number of books Abe has = 5 m = 5 x 7 = 35

So, the book they have in all = 21 + 35 = 56

5 0

3 years ago

Please answer 2.) a and b!

KatRina [158]

1.a. correct

1.b. $\sqrt{121} - \sqrt{9} = 11 - 3 = 8$

1.c. correct

1.d. $-\sqrt{36} - \sqrt{100} = -6 - 10 = -16$

2.a. 7 - x + 3w - 9

Terms: 7, -x, 3w, -9

Variables: x, w

Coefficients: -1, 3

Constants: 7, -9

2.b. -g + 8k - 3 - 7

Terms: -g, 8k, -3, -7

Variables: g, k

Coefficients: -1, 8

Constants: -3, -7

3.a. correct

3.b. correct

3.c. -5+ 4x = -x

4.a. 4(2x + 3) = 8x + 12

4.b. -2(3x + 4) = -6x - 8

4.c. -5(2x - 3) = -10x + 15

7 0

3 years ago

The corner grocery store sells apples for $1.19 per pound. Which store sells apples at a lower unit price than the corner store

Valentin [98]

Answer:

B- 3.48 ÷ 3

Step-by-step explanation:

3.48 ÷ 3= 1.16

Hope this helps

-mercury

4 0

3 years ago

Find the area of the part of the paraboloid z = 9 - x^2 - y^2 that lies above the xy-plane.

svetoff [14.1K]

Parameterize this surface (call it $S$ ) by

$\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(9-u^2)\,\vec k$

with $0\le u\le3$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec r_u\times\vec r_v=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k$

Then the area of $S$ is

$\displaystyle\iint_S\mathrm dA=\iint_S\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^3u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

$=\displaystyle2\pi\int_0^3u\sqrt{1+4u^2}\,\mathrm du=\boxed{\frac{37\sqrt{37}-1}6\pi}$

3 0

4 years ago

Evaluate the expression when c=-5.1 and d= - 7.8.

FrozenT [24]

Answer:

−31.5

Step-by-step explanation:

4 0

3 years ago

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