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Veronika [31]
3 years ago
10

What is 212 of 78 please HELP MEEEEEE

Mathematics
2 answers:
Serjik [45]3 years ago
6 0

Answer:

212 percent of 78 is 165.36

Step-by-step explanation:

HOPE IT'S HELP

ILY

Follow me plss

thank you

saveliy_v [14]3 years ago
6 0

Hi!don't really understand the question but if you talking about percent than the answer is 165.36.

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A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) t
solniwko [45]

Answer:

The upper confidence bound for population mean escape time is: 379.27

The upper prediction bound for the escape time of a single additional worker  is 413.64

Step-by-step explanation:

Given that :

sample size n = 26

sample mean \bar x =  371.08

standard deviation \sigma = 24.45

The objective is to calculate an upper confidence bound for population mean escape time using a confidence level of 95%

We need to determine the standard error of these given data first;

So,

Standard Error S.E = \dfrac{\sigma }{\sqrt{n}}

Standard Error S.E = \dfrac{24.45 }{\sqrt{26}}

Standard Error S.E = \dfrac{24.45 }{4.898979486}

Standard Error S.E = 4.7950

However;

Degree of freedom df= n - 1

Degree of freedom df= 26 - 1

Degree of freedom df= 25

At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

Similarly;

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 4.7950

The Margin of error = 8.18986

The upper confidence bound for population mean escape time is = Sample Mean + Margin   of  Error

The upper confidence bound for population mean escape time is =  371.08 +  8.18986

The upper confidence bound for population mean escape time is = 379.26986  \approx 379.27

The upper confidence bound for population mean escape time is: 379.27

b.  Calculate an upper prediction bound for the escape time of a single additional worker using a prediction level of 95%.

The standard error of the mean = \sigma \times \sqrt{1+ \dfrac{1}{n}}

The standard error of the mean = 24.45 \times \sqrt{1+ \dfrac{1}{26}}

The standard error of the mean = 24.45 \times \sqrt{1+0.03846153846}

The standard error of the mean = 24.45 \times \sqrt{1.03846153846}

The standard error of the mean = 24.45 \times 1.019049331

The standard error of the mean = 24.91575614

Recall that : At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

∴

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 24.91575614

The Margin of error = 42.55611149

The upper prediction bound for the escape time of a single additional worker  is calculate by the addition of

Sample Mean + Margin of Error

= 371.08 + 42.55611149

= 413.6361115

\approx 413.64

The upper prediction bound for the escape time of a single additional worker  is 413.64

8 0
4 years ago
18 red jellh beans is 36% of the total. how many jelly beand are there in all?​
miskamm [114]

There are 50 jellybeans

Multiply 18 ×100=1800

Divide 1800÷36=50

Hope this helps

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4 years ago
If boll sacks have 1 millon$ how much would he have if he spends 25910732$?
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Answer:

none

Step-by-step explanation:

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Rowan has 50$ in a saving jar and is putting in 5$ every week. Jonah has 10$ in his own jar is putting 15$ very week. Each of th
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C is true because the slope for johan is 15 compared to Rowans slope which is 5

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Please help me !!!!!!!!
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Step-by-step explanation:

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