Answer:
Option -c :5^ -12 . 2^ 40
Step-by-step explanation:
( 5^6 . 2^8 )( 5^-2 . 2^5 )
( 5^6 . 5^-2 ) ( 2^8 . 2^5 )
5^ -12 . 2^ 40
Option -c : 5^ -12 . 2^ 40
I hope im right!!
10 less than 5 times the value of a number -> 5a - 10
10 times the quantity of 12 more than one-fourth of a number -> 10(12+1/4a)
We have :
5a - 10 = 10(12 + 1/4a)
5a - 10 - [10(12 + 1/4a)] = 0
5a - 10 - (120 + 5/2a) = 0
5a -10 - 120 - 5/2a = 0
Group : (5a-5/2a) - (10 + 120) = 0
5/2a - 130 = 0
5/2a = 130 -> a = 130 : 5/2 = 52
Recheck : 5 x 52 - 10 = 250
10 x (12 + 1/4 x 52) = 10 x (12 + 13) = 10 x 25 = 250
Answer:
y = 4
Step-by-step explanation:
y - 1 = √y + 5
(y - 1)² = y + 5 (Square both sides)
y² - 2y + 1 = y + 5 (Expand left side)
y² - 3y - 4 = 0 (Subtract y and 5 from both sides)
(y + 1) (y - 4) = 0 (Factor)
y = -1, 4 (Use ZPP)
When we check y = -1 we see that it is not a solution so the answer is y = 4.
Answer: 3
Step-by-step explanation:
<u>Given</u>–
AB = 12 Cm
CD = 14 Cm
PO = 10 Cm
AP = 1/2 × 12 = 6 Cm
<u>Construction</u>–
Draw NO such that it is the perpendicular bisector of CB.
Hence,
ND = 1/2 × 14 = 7 Cm
To Find,
Measure of NO
<u>Solution</u>,
Here, PO Perpendicular to AB
Hence, APO is a right-angled triangle–
AO² = PO² + AP²
Or, AO² = 10 ² + 6 ²
Or, AO² = 36 + 100
Or, AO = √136 Cm
Or, AO = 11.66 Cm
Also, AO = OD = 11.66 Cm
( Radius of the same circle )
Now, in triangle OND,
OD² = ON² + ND ²
Or, 11.66 ² = ON² + 7²
Or, 136 = ON² + 49
Or, ON ² = 136 – 49
Or, ON ² = 87
Or, ON ² = √87
Or, ON = 9.3 Cm
Therefore, the appropriate length from center to CD is 9.3 Cm.