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Snowcat [4.5K]
2 years ago
7

Ruby drove 168 miles in 3 hours.

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
5 0

Answer:

56mph

12 more hours

Step-by-step explanation:

You might be interested in
For each expression below, select the letter that corresponds to the equivalent expression given above.
11111nata11111 [884]
Part 1)
(x²+15x+65)+(2x-5)*(3x+8)
(x²+15x+65)+(6x²+16x-15x-40)
(7x²+16x+25)

the answer Part 1) is the letter B
(7x²+16x+25)

Part 2)
(4x+1)*(3x-4)-(5x²-10x-12)
(4x+1)*(3x-4)-(5x²-10x-12)
(12x²-16x+3x-4)-(5x²-10x-12)
(7x²-3x+8)

the answer Part 2) is the letter D
(7x²-3x+8)

Part 3) 
(8x²+19x+4)+(3x+2)*(x-5)
(8x²+19x+4)+(3x²-15x+2x-10)
(11x²+6x-6)

the answer part 3) is the letter A
(11x²+6x-6)

Part 4) 
(6x+1)*(3x-7)-(7x²-34x-20)
(18x²-42x+3x-7)-(7x²-34x-20)
(11x²-5x+13)

the answer Part 4) is the letter C
(11x²-5x+13)

3 0
3 years ago
What is the specific method called on #3
IceJOKER [234]

Answer:

subtraction

Step-by-step explanation:

6 0
3 years ago
JUST ANSWER PLEASE!!! QUICK
jeka57 [31]

Answer:

<u>Options 1 and 3</u>

Step-by-step explanation:

We should know that, the system of linear equations can be treated as matrices, i.e: we can modify or make any operations provide that we must apply the same operation for all terms of each equation.

Given:  the solution for the following system is (2,9)

Px + Qy = R  ⇒(1)

Tx + Uy = V  ⇒(2)

We will check which system of equation has the same solution.

<u>System A)</u>  Px + Qy = R

                  (P+T)x + (Q+U)y = R+V  ⇒(3)

So, By summing (1) and (2) we will get the equation (3)

So, system A has the same solution (2,9)

<u>System B)</u> Px + Qy = R

                 (P+2T)x + (Q+2U)y = R-2V  ⇒(4)

By multiplying equation (2) by 2 and add with equation (1), we will get:

 (P+2T)x + (Q+2U)y = R+2V

Which is not the same as equation (4)

So, system B has not the same solution (2,9)

<u>System C)</u> (T-P)x + (U-Q)y = V-R  ⇒(5)

                  Tx + Uy = V  

By multiplying equation (1) by -1 and add with equation (2), we will get the equation (5)

So, system C has the same solution of (2,9)

<u>System D)</u> (T-P)x + (Q+U)y = V-R  ⇒(6)

                  Tx + Uy = V  

We cannot get equation (6) by the same operation over equation (1)

Note the coefficient of x and y⇒ (T-P) and (Q+U)

They must be (T+P) and (Q+U) <u>OR </u>(T-P) and (Q-U)

So, system D has not the same solution of (2,9)

<u>System E)</u> (5T-P)x + (5U-Q)y = V-5R ⇒ (6)

                  Tx + Uy = V  

By subtract equation (1) from 5 times equation (2), we will get:

(5T-P)x + (5U-Q)y = 5V-R

Which is not the same as equation (6)

So, system E has not the same solution (2,9)

As a conclusion, the systems which have the same solution are:

<u>Options 1 and 3</u>

5 0
2 years ago
What is the least common multiple or 8 and 2
Rufina [12.5K]
The <span>least common multiple or 8 and 2 is 8.</span>
6 0
3 years ago
Read 2 more answers
If a over 2 equals b over 3 then b over a equals what?
ikadub [295]
A/2=b/3
b/a
a=2/3b
b=3/2a
4b/9a
5 0
3 years ago
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