I have a pink eye and I’m in class and it hurts bad when I look at the screen … and it starts to water .. what can I do ?

Mathematics

2 answers:

aliya0001 [1]2 years ago

5 0

Answer:

Go see the nurse!

Step-by-step explanation:

Brainliest!

svlad2 [7]2 years ago

4 0

Answer:

Go to the nurses office

Step-by-step explanation:

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The reflection of a Quadrant II point is located in Quadrant I. Assuming no error was made, what kind of reflection occurred?

gizmo_the_mogwai [7]

Answer:

A reflection across the y- axis

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y) → (-x, y)

A point in the second quadrant (- x, y)

Under reflection in the y- axis is (x, y) ← point in first quadrant

3 0

2 years ago

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Answer Question number 5 <br> Plzzzzzz

loris [4]

Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

last term = 4 1/3 = 13/3

nth term = a +(n-1)d

$\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18$

Middle terms are 9the term and 10th term

$t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3$