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OLEGan [10]
2 years ago
9

Class.object.method is an example of using the ______ to access the elements of a class.

Computers and Technology
1 answer:
Aleonysh [2.5K]2 years ago
6 0

Answer:

dot operator

I hope I helped ^-^

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Which device or software application detects errors in system configurations?
amm1812
Error-correcting code memory
5 0
3 years ago
________ programming is a method of writing software that centers on the actions that take place in a program.
Norma-Jean [14]

Answer: Procedural software

Explanation:

Procedural software programming is the programming mechanism that functions through splitting the data and functions of the program.This programming focuses on subroutines or action for functioning as per call of procedure.

  • It can carry out computation through steps in linear manner or top-to-bottom manner.
  • These steps consist of data ,subroutines, routines and other variable and functions for working.
8 0
3 years ago
Assume that name and age have been declared suitably for storing names (like "abdullah", "alexandra" and "zoe") and ages respect
schepotkina [342]

Answer:

Explanation:

It is assumed that name and age have been declared suitably for storing names and ages. so the following is the code to read in a name  and age and printout the message "the age of name is age. "

cin >> Name;

cin >> Age;

cout << "The age of " << Name << " is " << Age << ".";

7 0
3 years ago
Write a function called mul_time that takes a Time_Elapsed object and a number and returns a new Time_Elapsed object that contai
lisov135 [29]

# Write a function called mul_time that takes a Time object and a number and

# returns a new Time object that contains the product of the original Time and

# the number.

# Then use mul_time to write a function that takes a Time object that

# represents the finishing time in a race, and a number that represents the

# distance, and returns a Time object that represents the average pace (time

# per mile).

# Current Status: Complete

class Time(object):

   """ represents the time of day.

   attributes: hour, minute, second"""

time = Time()

time.hour = 3

time.minute = 0

time.second = 0

def time_to_int(time):

   minutes = time.hour * 60 + time.minute

   seconds = minutes * 60 + time.second

   return seconds

def int_to_time(seconds):

   new_time = Time()

   minutes, new_time.second = divmod(seconds, 60)

   time.hour, time.minute = divmod(minutes, 60)

   return time

def mul_time(time, multicand):

   time_int = time_to_int(time) * multicand

   new_time = int_to_time(time_int)

   if new_time.hour > 12:

       new_time.hour = new_time.hour % 12

#    print ("New time is: %.2d:%.2d:%.2d"

#    % (new_time.hour, new_time.minute, new_time.second))

   return new_time

# mul_time(time, 2)

def race_stats(time, distance):

   print ("The finish time was %.2d:%.2d:%.2d"

         % (time.hour, time.minute, time.second))

   print "The distance was %d miles" % (distance)

   average = mul_time(time, (1.0 / distance))

   print ("The average is: %.2d:%.2d:%.2d per mile"

         % (average.hour, average.minute, average.second))

race_stats(time, 3)

7 0
2 years ago
More registers appear to be a good thing, in terms of reducing the total number of memory accesses a program might require. Give
gulaghasi [49]

Answer:

Following is given the answer step by step:

Explanation:

First of all we will write a program using MARIE that will support the statement: Sum = (A + B) - (C + D). All the necessary comments are given in front of each statement:

Load    A                   # variable A will be loaded

Add     B                  # B will be added to A

Store   Temp1         # A + B will be stored in Temp1

Load    C                  # C will be loaded in memory

Add     D                 # D will be added to C

Store   Temp2         # C + D will ge stored in Temp2

Load    Temp1         # Temp1 will be loaded in the memory

Subt     Temp2         # Temp2(A + B) get subtracted from Temp1(A - B)

Store    Sum             # (A + B) - (C + D) will get stored in Sum.

We can see from above program that memory is accessed 9 times. While if C + D get executed first than memory accesses will be reduced to 7.

Above same program could be written using an architecture of 4 registers:

  • R1
  • R2
  • R3
  • R4

The program is as follows:

Load   R1 , A     #A  will be loaded into R1

Load   R2 , B    # B will be loaded into R2

Add     R1 , R2    # R2 gets added to R1 and the result is stored in R1 (A + B)

Load   R3 , C      # C loaded into R3

Load   R4 , D     # D loaded into R4

Add    R3 , R4   # Value in R4 gets added into R3 and R3 becomes (C + D)

                          #no memory accesses required for this operation

Subt   R1 , R4     #R4 (C + D) gets subtracted from R1 (A + B)

                         #no memory accesses required for this operation

Store  Sum        # The recent value will be stored into Sum

Here memory is accessed 5 times in total.

<h2>I hope it will help you!</h2>
8 0
3 years ago
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