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shusha [124]
2 years ago
14

A Chief Security Officer (CSO) has asked a technician to devise a solution that can detect unauthorized execution privileges fro

m the OS in both executable and data files, and can work in conjunction with proxies or UTM. Which of the following would BEST meet the CSO's requirements?
A. Fuzzing.
B. Sandboxing.
C. Static code analysis.
D. Code review.
Computers and Technology
1 answer:
VikaD [51]2 years ago
8 0

A solution which would best meet the CSO's requirements is: B. Sandboxing.

<h3>What is a sandbox?</h3>

A sandbox can be defined as an isolated environment in a computer system or on a network that is designed and developed to mimic end user operating system (OS) and environments, so as to detect unauthorized execution privileges from the operating system (OS).

In cybersecurity, sandboxing is typically used to safely execute suspicious code and data files without causing any harm to the host device or network. Also, sandboxing can work in conjunction with proxies or unified threat management (UTM).

Read more on sandboxing here: brainly.com/question/25883753

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Write a program that first gets a list of integers from input. The input begins with an integer indicating the number of integer
meriva

Answer:

package b4;

import java.util.Scanner;

public class TresholdValue {

public static void main(String[] args) {

 // Create an object of the Scanner class to allow for user's input

 Scanner input = new Scanner(System.in);

 // Create a prompt to allow users to enter the set of integers

 System.out.println("Please enter the set of integers, each followed by a space : ");

 // Get the first integer from the set of inputs.

 // Parse the input and convert it into an integer

 // by using the Integer.parseInt() method.

 // Store the result in an integer variable.

 int first = Integer.parseInt(input.next());

 // Create an integer array to hold the other numbers (first number excluded).

 // The array should have a length equal in value to the first number in the set.

 // This has been stored in a variable called "first".

 int[] intarray = new int[first];

 // Create a while loop that populate the intarray with the set of numbers

 int i = 0;

 while (input.hasNext() && i < intarray.length) {

  intarray[i] = Integer.parseInt(input.next());

  i++;

 }

 // Get the last value (threshold) from the intarray.

 // The threshold value is the last element in the array.

 int lastvalue = intarray[intarray.length - 1];

 // Create a prompt before displaying the set of values that are less than or

 // equal to the threshold value.

 System.out.println("Values less than or equal to the threshold value (" + lastvalue + ") are : ");

 // Create a loop to cycle through the array.

 // At each cycle, the element is checked if or not it is less than or equal to

 // the threshold value.

 // If it is less than or equal to, the number is printed.

 for (int j = 0; j < intarray.length - 1; j++) {

  if (intarray[j] <= lastvalue) {

   System.out.print(intarray[j] + " ");

  }

 }

 // (Optional) Close the Scanner object to prevent resource leak

 input.close();

}

}

Explanation:

The program has been written in Java. The source code file has been attached to this response. Please download it for better readability. The code contains comments explaining what goes on on each segment of the code.

Hope this helps!

Download java
3 0
3 years ago
Read 2 more answers
One condition for deadlocks is the circular-wait condition. One way to ensure that this condition never holds is to impose a tot
Artyom0805 [142]
<h2>Dead lock is possible in Bank Transactions</h2>

Explanation:

Let us understand the term "Dead lock"

A deadlock is a situation where whole set of process is locked, since each of the process is waiting or holding the resource of another process. Each process will be interdependent and waiting for the same resource.

Deadlock is possible during bank transaction in the following situation:

A & B are two accounts where A tries to transfer funds to B and B tries to transfer fund to A.

When both tries to transfer funds at the same time, deadlock occurs.

A deadlock can be avoided by any one of the four methods.

They are: Mutual exclusion, No preemption, circular wait, hold and wait.

4 0
3 years ago
Read 2 more answers
Consider the following code segment. for (int a = 0; a &lt; 10; a++) { for (int b = 10; b &gt; a; b--) { System.out.print("#");
Ket [755]

Answer:

55

Explanation:

Given the codes as below:

  1.        for (int a = 0; a < 10; a++)
  2.        {
  3.            for (int b = 10; b > a; b--)
  4.            {
  5.                System.out.print("#");
  6.            }
  7.        }

There are two layer loops in the code. The outer loop (Line 1) will run for 10 iterations by traversing through a = 0 to a=9. However, the inner loop  (Line 3) will run for 10 + 9 +  8 + 7 +...+ 1 = 55 iterations.

Since the print statement is within the inner loop (Line 5) and therefore the number of printed "#" symbols is dependent on the number of iterations of the inner loop. There will be 55 "#" symbols printed.

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The automotive system that connects the engine and the transmission to the wheels is called the
insens350 [35]
I believe the driveshaft 

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3 years ago
When presentations are being shown to an audience of over fifty people, how they should be displayed?
Anarel [89]
Full screeennn !!!!!!
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