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zloy xaker [14]
2 years ago
7

A circular mirror is surrounded by a square metal frame. The radius of the mirror is 2x. The side length of the metal frame is 8

x. What is the area of the metal frame?
Mathematics
2 answers:
ValentinkaMS [17]2 years ago
8 0
The answer is 183.43x 2 because of how it’s surrounded by a square frame and then the radius
Schach [20]2 years ago
3 0

Answer:

183.43x2

Step-by-step explanation:

Area of the entire frame = (14x)2 = 196x2

Area of the mirror = pi(2x)2 = 4x2(pi)

Area of the frame surrounding the mirror = (196 - 4pi)x2 = 183.43x2

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Domain and Range for the function f(x)=5IXI is
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Answer:

The domain of the function f(x) is:

\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

The range of the function f(x) is:

\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

Step-by-step explanation:

Given the function

f\left(x\right)=5\left|x\right|

Determining the domain:

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis.

It is clear that the function has undefined points nor domain constraints.

Thus, the domain of the function f(x) is:

\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Determining the range:

We also know that range is the set of values of the dependent variable for which a function is defined.  

In other words,  

  • Range refers to all the possible sets of output values on the y-axis.

We know that the range of an Absolute function is of the form

c|ax+b|+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k

k=0

so

Thus, the range of the function f(x) is:

\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

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