, Two triangles are similar. Triangle ABC has side lengths of AB = 10, BC = 6, CA = 7. Triangle XYZ has a side length of XY = 8. Find YZ.
The answer is C because the angle equal each other.
Answer:
A
Step-by-step explanation:
=(2(3x+4)(x−1))(x+−3)
=(2(3x+4)(x−1))(x)+(2(3x+4)(x−1))(−3)
=6x3+2x2−8x−18x2−6x+24
=6x3−16x2−14x+24
Answer:
<em>We </em><em>know </em><em>that </em><em>exterior </em><em>angle </em><em>of </em><em>a </em><em>triangle </em><em>is </em><em>equal </em><em>to </em><em>the </em><em>sum </em><em>of </em><em>two </em><em>opposite </em><em>interior </em><em>angle</em><em>.</em>
Step-by-step explanation:
<A = 4y
< B = 3y + 6°
<BCD = 111°
Now
<BCD = <A + <B( exterior angle of a triangle is equal to the sum of two opposite interior angle)
111° = 4y + 3y + 6°
111° - 6° = 7y
105° =7y
Therefore y = 15°
The measure of <A = 4*15°= 60°
Total of 90 fish:
c + p = 90
Charlie gave 1/4 c to Peter. Now
Charlie has c - (1/4) c
Peter has p + (1/4) c
Peter gave 2/5 of his to Charlie. Now
Peter has p + (1/4) c - 2/5( p + (1/4) c )
Charlie has c - (1/4) c + 2/5( p + (1/4) c )
And then they had equal number:
c - (1/4) c + 2/5( p + (1/4) c ) = p + (1/4) c - 2/5( p + (1/4) c )
Let's do the easy subtractions then multiply by 20 to clear the fractions,
(3/4) c + 2/5( p + (1/4) c ) = 3/5( p + (1/4) c )
15c + 8p + 2c = 12p + 3c
14c = 4p
7c = 2p
c + p = 90
2c + 2p = 180
2c + 7c = 180
9c = 180
c = 20
p = 70
Answer: Charlie started with 20, Peter with 70
Check:
Initially C:20, P:70
1/4(20)=5 to P
C:15, P:75
(2/5) 75 = 30 to C
C:45, P45
Good
