Answer:
11.since diagonal are equal of rectangle
QS=RT
4x+6=6x-4
6+4=6x-4x
2x=10
x=10/2
x=5
now
diagonal :4x+6=4*5+6=<u>26</u>
12.
again
QS=RT
9x+12=11x-10
12+10=11x-9x
2x=22
x=11
now
diagonal=9*11+12=99+12=<u>111</u>
Answer:
[50, 410]
Step-by-step explanation:
If the plumber works 0 hours, he still charges $50, so that is the minimum of the range of charges.
If the plumber works 8 hours, his hourly charge of 8×$45 = $360 is added to his fixed charge of $50 for a total of $410. That is the maximum of the range of daily charges.
The range of the function is $50 to $410.
Answer:
11.6--------------------------------------
Explanation:
See the attached image for a visual reference
The distance from point D to E is 21 units. Point C is the midpoint, so CD is 10.5 units long (21/2 = 10.5)
We have a right triangle ACD. The legs are
AC = 5
CD = 10.5
The hypotenuse is
AD = x
Because AD is another radius of the same circle
Use the pythagorean theorem to find x
a^2 + b^2 = c^2
5^2 + 10.5^2 = x^2
25 + 110.25 = x^2
135.25 = x^2
x^2 = 135.25
x = sqrt(135.25)
x = 11.629703349613
which rounds to
11.6 when rounding to the nearest tenth (one decimal place)
Answer:
197.2 million
Step-by-step explanation:
The appropriate exponential equation for the population is ...
p(t) = 172.0e^(0.019t)
Then we can compute for t=7.2:
p(7.2) = 172.0e^(0.019·7.2) ≈ 172.0·1.146599 ≈ 197.2
7.2 minutes from now, the population will be about 197.2 million.
___
For continuous growth (or continuous compounding), the exponential formula is ...
f(t) = (value at t=0)×e^(rt)
where r is the growth rate in one unit of time, and t is the number of time periods.
Answer:
Width of the rectangular Park = 11 feet
Step-by-step explanation:
Given that the total length of the fencing is 62 feet. As has to be fenced around a rectangular park , it would be the perimeter of the rectangular park.
Also Shana wants the length of the run to be 20 feet. Hence the length of the park is 20 feet.
Here we will use the formula for perimeter to find the width of the run
Perimeter = 2(l+w)
62=2(l+w)
l+w = 
l+w=31
20+w=31
w=31-20
w=11
Hence the width of the run for her dog in park would be 11 feet.