Number 6 and 7 please

Mathematics

1 answer:

madreJ [45]2 years ago

8 0

I’m pretty sure #6 is 3.5 mph and #7 is 60 acres per hour

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What addition equations can make 16?

sleet_krkn [62]

15 + 1; 14 + 2; 13 + 3; 12 + 4; 11 + 5; 10 + 6; 9 + 7; 8 + 8

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3 years ago

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Due tonight help me out please

aleksley [76]

The average rate of change is the slope.

The slope is equal $\frac{y2-y1}{x2-x1}$ , if we were to do that for each set of points, we get the slope is always 8.

Thus the average rate of change is 8.

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2 years ago

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romanna [79]

In lines y=mx+b, for them to be parallel they must have the same slope, m, in the equation of the line...

y=4x+1 and y=-4x+5 not parallel

y=x-2 and y=x-1 these lines are parallel

y=x/4+2 and y=x/2+2 not parallel

y=x/5+1 and y=-x/5+2 not parallel

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3 years ago

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Help thankss <br>answer is <br><img src="https://tex.z-dn.net/?f=%20%28%20-%2014.0%29" id="TexFormula1" title=" ( - 14.0)" alt="

lyudmila [28]

We have point $P=(x_0,y_0)=(2,-4)$ , so first calculate $f'(x_0)$ . There will be:

$y=f(x)=2x^3-5x^2\\\\\\\\f'(x)=\big(2x^3-5x^2\big)'=\big(2x^3\big)'-\big(5x^2\big)'=2\big(x^3\big)'-5\big(x^2\big)'=\\\\=2\cdot3x^2-5\cdot2x=\boxed{6x^2-10x}\\\\\\\\f'(x_0)=f'(2)=6\cdot2^2-10\cdot2=6\cdot4-20=24-20=\boxed{4}$

Now, we can write the equation of the normal line as:

$y-y_0=-\dfrac{1}{f'(x_0)}(x-x_0)\\\\\\ y-(-4)=-\dfrac{1}{4}(x-2)\\\\\\y+4=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\\\y=-\dfrac{1}{4}x+\dfrac{1}{2}-4\\\\\\\boxed{y=-\dfrac{1}{4}x-\dfrac{7}{2}}$

Normal line (and every line) crosses x-axis when y = 0, so coordinates of A:

$\boxed{y=0}\qquad\qquad\text{and}\\\\\\y=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\
0=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\\dfrac{1}{4}x=-\dfrac{7}{2}\quad|\cdot4\\\\\\x=-\dfrac{7\cdot4}{2}\\\\\\x=-7\cdot2\\\\\\\boxed{x=-14}\\\\\\\boxed{A=(-14,0)}$

8 0

3 years ago

Plz help me plz plzplzplzplz

Archy [21]

Answer:

so it's just a compare and contrast statement. 225 is less than 300 or 300 is more than 225

3 0

3 years ago