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2 years ago

Number 6 and 7 please

Mathematics

1 answer:

madreJ [45]2 years ago

8 0

I’m pretty sure #6 is 3.5 mph and #7 is 60 acres per hour

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If y=-5 when x=2,find y when x=8

LenaWriter [7]

You can’t really know the y value unless you’re told that they’re both directly proportional. if so, then check out the pic

5 0

3 years ago

A gold mine is projected to produce $52,000 during its first year of operation, $50,000 the second year, $48,000 the third year,

marshall27 [118]

Answer:

its present worth is nearest to 483,566

Option d) 483,566 is the correct answer

Step-by-step explanation:

Given that;

gold mine is projected to produce $52,000 during its first year

produce $50,000 the second year

produce $48,000 the third year

the mine is expected to produce for 20yrs; i.e n = 20

annual interest rate = 4% = 0.04%

now let P represent the present worth

we determine the present worth ;

Present worth ⇒ Cashflow(Uniform series present worth) - (2000)(uniform gradient present worth)

⇒Cashflow(P | A,i%,n) - (2000)(P | G,i%,n)

= 52000[ ((1+i)ⁿ - 1) / (i(1+i)ⁿ) ] - (2000)[ {((1+i)ⁿ - 1) / (i²(1+i)ⁿ))} - (n/i(1 + i)ⁿ) ]

= 52000[ ((1+0.04)²⁰ - 1) / (0.04(1+0.04)²⁰) ] - (2000)[ {((1+0.04)20 - 1) / ((0.04)²(1+0.04)²⁰))} - (20/0.04(1 + 0.04)²⁰) ]

= 52000[ ((1.04)²⁰ - 1) / (0.04(1.04)²⁰) ] - (2000)[ {((1.04)²⁰ - 1) / ((0.04)²(1.04)²⁰))} - (20/0.04(1.04)²⁰) ]

= 52000[ ((2.191123 - 1) / (0.04(2.191123) ] - (2000)[ {((2.191123 - 1) / ((0.0016)(2.191123))} - (20/0.04(2.191123) ]

= 52000(1.191123/0.08764) - (2000){( 1.191123/0.003506) - (20/0.87645)}

= 52000(13.59033) - (2000)(339.7582 - 228.1935)

= 52000(13.59033) - (2000)(111.5647)

= 706695.6 - 223129.4

= 483,566.2 ≈ 483,566

Therefore its present worth is nearest to 483,566

Option d) 483,566 is the correct answer

4 0

3 years ago

A car advertisement claims that a certain car can accelerate from rest to 70 km/hr in 7 seconds find the car acceleration

iVinArrow [24]

Answer:

acceleration $\approx 2.78\,\,\frac{m}{s^2}$

Step-by-step explanation:

The acceleration is the change in velocity per unit of time.

Therefore to have this rate in appropriate units that can combine, we re-write the change from 0 to 70 km/h in meters per second using:

$70 \frac{km}{h} = \frac{70000}{3600} \frac{m}{s}$

so in this case the acceleration becomes:

$accel=\frac{change\,\,vel}{change\,\,time} =\frac{70000m}{3600\,*7\,s^2} \approx 2.78\,\,\frac{m}{s^2}$

7 0

3 years ago

X + 3y = -3 solve for Y (ex. y= 3 + 5x

AnnyKZ [126]

Answer:

y = -1/3x - 1

Step-by-step explanation:

Let's solve for y.

Step 1: Add -x to both sides.

x+3y+−x=−3+−x

3y=−x−3

Step 2: Divide both sides by 3.

y=-1/3x-1

$\frac{-1}{3} x-1$

3 0

2 years ago

What is the interquartile range of this data? 6 8 9

vladimir1956 [14]

Answer:

Step-by-step explanation:

Just subtract the first quartile form the third quartile.

third quartile - first quartile

32 - 8 = 24 IQR

FIRST quartile: 8

SECOND quartile: 20

THIRD quartile: 32

So the IQR is 24

Hope this helps :)

3 0

3 years ago

Read 2 more answers