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Luda [366]
2 years ago
13

Please help Worth 20 points Show the work

Mathematics
1 answer:
Dvinal [7]2 years ago
4 0

Answer:

  • area: 60π cm² ≈ 188.5 cm²
  • volume: 63π cm³ ≈ 197.9 cm³
  • doubling the radius

Step-by-step explanation:

<h3>(a)</h3>

The surface area of a right cylinder is given by the formula ...

  SA = 2πr(r +h) . . . . . radius r, height h

Filling in the given values, we find the area to be ...

  SA = 2π(3 cm)(3 +7 cm) = 60π cm² ≈ 188.5 cm²

__

<h3>(b)</h3>

The volume of the cylinder is given by the formula ...

  V = πr²h . . . . . radius r, height h

Filling in the given values, we find the volume to be ...

  V = π(3 cm)²(7 cm) = 63π cm³ ≈ 197.9 cm³

__

<h3>(c)</h3>

The volume is proportional to r², so doubling the radius will multiply the volume by 2² = 4.

The volume is proportional to the height, so multiplying the height by 3 will multiply the volume by 3.

  4 > 3, so doubling the radius gives the most volume

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Answer:

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Step-by-step explanation:

g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2

For absolute minimum we take the minimum values of x and y.

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Plugging in the minimum values in the function.

g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\

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Plugging in the maximum values in the function.

g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\

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