Answer:

Step-by-step explanation:
Note that the squares are on the sides of these triangles are on the hypotenuse/one leg.
We know that the area of a square is
where l is the length. Since we know the area, we can find the square root of the area to find the side length.
So the side lengths are
and
.
Since we know the hypotenuse is
and one of the legs is
, we can use the Pythagorean Theorem to find the missing side.
The Pythagorean Theorem states that
, where c is the hypotenuse and a/b are the legs.
We know the <em>hypotenuse </em>and <em>a leg</em>, so we can substitute inside

Squaring a square root is the same as doing nothing.

Hope this helped!
Answer:
the largest divisor is less than the square root of that number
Step-by-step explanation:
Pick any number between 900 and 950 . For example I choose 937 . Now taking the square root of 937 would give 30.61
So divide 937 with all the primes less than 30.61
937/2, 937/3, 937/5,...................937/29
29 would be the largest divisor which is less than the square root of 937 .
29< 30.61
But if you check 937 does not divide wholly with any of the primes hence it is a prime number itself.
If any number such 925 is chosen and it gets divided wholly by another prime like 5
925 /5= 185 so it is not a prime number
Answer:
1.38 to the nearest hundredth.
Step-by-step explanation:
Dividing:
x + 1 ) 3x - 1 ( 3
3x + 3
-4
so (3x - 1) / (x + 1) = 3 - 4 / x+ 1
Integral of (3 - 4 / x+1 ) = 3x - 4 ln(x + 1)
Between limits of 1 and 2 we have:
(3(2) - 4 ln 3) - (3 - 4 ln2)
= 1.6056 - 0.2274
= 1.3782.
Answer:
0.8857142857
Step-by-step explanation:
31 divided by 35 equals 0.8857142857
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Answer:
y>0.5
Step-by-step explanation:
Rearrange the equation so "y" is on the left and everything else on the right.
Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>
Shade above the line for a "greater than" (y> or y≥)
or below the line for a "less than" (y< or y≤).
y+x>1
-y -y
x>1-y
2x+y<3
-y -y
2x<3-y
divide by 2
x<1.5-y/2
1.5-y/2>1-y
-1.5+y -1.5+y
<u>y>0.5</u>