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2 years ago

Find the missing measure. 50° x°

Mathematics

1 answer:

Slav-nsk [51]2 years ago

8 0

Answer:

x = 129° ( linear pair then vertically opp angles)

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If the mass of the

DaniilM [7]

Answer:

the mass of liquid is 1,050 g

Step-by-step explanation:

subtract the total mass with the mass of the container

7 0

3 years ago

Given: a ∥ b and ∠1 ≅ ∠3

gayaneshka [121]

Answer:

∠1 ≅ ∠2

Step-by-step explanation:

As shown in the figure:

We need to prove e ∥ f using the congruent angle.

So, check the options:

A) ∠2 ≅ ∠4 ⇒ (Wrong)

B) ∠1 ≅ ∠2 ⇒ (True) because a ∥ b (Given)

C) ∠2 ≅ ∠3 ⇒ It is required to prove that to prove e ∥ f , it can't be used.

D) ∠1 ≅ ∠4 ⇒ (Wrong)

The complete sentence will be:

We see that ∠1 ≅ ∠2 by the alternate exterior angles theorem.

Therefore, angle 2 is congruent to angle 3 by the transitive property.

5 0

3 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago

How do I solve x for midsegments

satela [25.4K]

You basically just divide what ever number by 2

7 0

4 years ago

Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of s

Elenna [48]

I will rewrite the question for better understanding:

Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of samples in her neighborhood. It takes Ashley 2/3 of a minute to prepare one bag. It takes each of her friends 75% longer to prepare a bag. How many hours will it take Ashley and 4 of her friends to prepare 1575 bags of samples?

Answer:

5.3 hours

Explanation:

1) Time it takes Ashley to preprate one bag:

2/3 min

2) Time it takes each friend of Ashley: 75% more than 2/3 min

75% × 2/3 min = 0.75 × 2/3 min = 3/4 × 2/3 min= 2/4 min = 1/2 min = 0.5 min

2/3 min + 1/2 min = 7/6 min

3) Time it takes Ashley and the 4 friends working along to prepare one bag:

Convert each time into a rate, since you can set that the total rate of Ashley along with her four friends is equal to the sum of each rate:

Rate of Ashley: 1 bag / (2/3) min = 3/2 bag/min

Rate of each friend: 1 bag / (7/6) min = 6/7 bag/min

Rate of Ashley and 4 friends = 3/2 bag/min + 4 × 6/7 bag/min = (3/2 +24/7) bag/min = 69/14 bag/min

4) Time of prepare 1575 bags of samples:

time = number of bags / number of bags per min = 1,575 bags / (69/14) bags/min = 319.56 min

5) Convert minutes to hours:

356.56 min × 1 hour / 60 min = 5.3 hours

3 0

3 years ago