Step-by-step explanation:
if we translate (shift) a function g(x) to the right by k to create h(x), then h(x) creates the same functional values as g(x), but they happen now for higher x ("later", if you consider x as a kind of time).
so, e.g.
h(0) = g(0 - k)
or
g(0) = h(0 + k)
and to translate to the left by k has the opposite effect. the original results happen "earlier" on the x-axis.
so, e.g.
h(0) = g(0 + k)
or
g(0) = h(0 - k)
so, all we need to do is to replace every occurrence of x by (x - k) if shifting right, or by (x + k) if shifting left.
our graph is
10x² - 2x + 4y² - 4y = 40
so, translating this 4 units to the right gives us
10(x - 4)² - 2(x - 4) + 4y² - 4y = 40
10(x² - 8x + 16) - 2x + 8 + 4y² - 4y = 40
10x² - 80x + 160 - 2x + 8 + 4y² - 4y = 40
10x² - 82x + 4y² - 4y = -128
translating the original graph 3 units to the left gives us
10(x + 3)² - 2(x + 3) + 4y² - 4y = 40
10(x² + 6x + 9) - 2x - 6 + 4y² - 4y = 40
10x² + 60x + 90 - 2x - 6 + 4y² - 4y = 40
10x² + 58x + 4y² - 4y = -44
