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horsena [70]
2 years ago
9

Tickets to a play cost $10 at the door and $8 in advance. The theater club wants to raise at least $800 from the sale of the tic

kets from the play. Write and graph an inequality for the number of tickets the theater club needs to sell. If the club sells 40 tickets in advance how many does it need to sell at the door to reach its goal? use x to represent the number of tickets sold at the door. use y to represent the number of tickets sold in advance.
Write and graph an inequality for the number of tickets the theater club needs to sell. Use x to represent the number of tickets sold at the door and y to represent the number of tickets sold in advance.
Mathematics
1 answer:
jenyasd209 [6]2 years ago
6 0

Standard form:

10x + 8y < 800

Slope intercept form:

y < (-5/4)x + 100

Slope: -5/4

y-intercept: 100

Hope this helps

TT - dravenfact8

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3x - 2x + 4 = 5x - 4x - 8

First, let's focus on the left side of the problem (3x - 2x + 4). Let's subtract 3x - 2x which will get us 1, and since a variable by itself is considered 1, we can just put the variable.
1 + 4 = 5x - 4x - 8

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x = 4 = x - 8

Third, we can now cancel out x on each side. This will leave us with 4 = -8, which is false, meaning that there is no solution to this problem.

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A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po
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Answer:

a. See Attachment 1

b. PT = 12.3\ m

c. HT = 31.1\ m

d. OH = 28.4\ m

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OT}{20}

Multiply both sides by 20

20 * tan50 = \frac{OT}{20} * 20

20 * tan50 = OT

20 * 1.1918 = OT

23.836  = OT

OT = 23.836

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

tan30 = \frac{OP}{20}

Multiply both sides by 20

20 * tan30 = \frac{OP}{20} * 20

20 * tan30 = OP

20 * 0.5774= OP

11.548 = OP

OP = 11.548

PT = OT - OP

PT = 23.836 - 11.548

PT = 12.288

PT = 12.3\ m (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

HT^2 = OT^2 + OH^2

Substitute 20 for OH and OT = 23.836

HT^2 = 20^2 + 23.836^2

HT^2 = 400 + 568.154896

HT^2 = 968.154896

Take Square Root of both sides

HT = \sqrt{968.154896}

HT = 31.1\ m <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OH}{OT}

Multiply both sides by OT

OT * tan50 = \frac{OH}{OT} * OT

OT * tan50 = {OH

OT * 1.1918 = OH

Substitute OT = 23.836

23.836 * 1.1918 = OH

28.4= OH

OH = 28.4\ m<em> (Approximated)</em>

5 0
3 years ago
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