All categories

2 years ago

Factor completely 4h2 g. H(4h g) g(4h2) Prime gh(4h 1).

1 answer:

3 0

The expression can be divided by one and itself only. Then the expression is a prime expression. The correct option is C.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The expression is $\rm 4h^2 + g$

The expression can be written as

$\rm (2h)^2 + g$

The expression can not be the real factor.

Since the expression can be divided by one and itself only.

Then the expression is a prime expression.

Thus, the correct option is C.

More about the factorization link is given below.

brainly.com/question/6810544

You might be interested in

At noon, the temperature in Tempest, California was

Gala2k [10]

Answer:

The change was 18 ° F

Step-by-step explanation:

We know that:

At noon, the temperature in Tempest, California was 78°F

At midnight the temperature is: 60°F.

To find the temperature drop, subtract the temperature of noon with the temperature at midnight.

$Change= 78\°F - 60\°F = 18\°F$

<h3>The change was 18 ° F</h3>

4 0

3 years ago

A girl cut off 2/5 of a ribbon. The piece she cut off was 5 meters long.How

valentinak56 [21]

Answer:

12.5

Step-by-step explanation:

5/2*5=12.5

7 0

3 years ago

Read 2 more answers

2 [ 32 - (4-1) to the third power ]

Tems11 [23]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

I give 30 points! Please don't put anything, please try to help me

antoniya [11.8K]

It says pdf loading so i can’t help sorry

3 0

3 years ago

Prove divisibility 45^45·15^15 by 75^30

Anuta_ua [19.1K]

Answer:

$3^{75}$

Step-by-step explanation:

We are asked to divide our given fraction: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(3*15)^{45}=3^{45}*15^{45}$

$75^{30}=(5*15)^{30}=5^{30}*15^{30}$

Substituting these values in our division problem we will get,

$\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}$

$\frac{3^{45}*15^{60}}{5^{30}*15^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{45}*15^{60-30}}{5^{30}}$

$\frac{3^{45}*15^{30}}{5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{3^{45}*(3*5)^{30}}{5^{30}}$

$\frac{3^{45}*3^{30}*5^{30}}{5^{30}}$

Upon canceling out $5^{30}$ we will get,

$3^{45}*3^{30}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$3^{45+30}$

$3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

8 0

3 years ago