Answer:
Surface area of Cube Y is 3 times greater than the surface area of cube X
Step-by-step explanation:
Surface area of a cube,A = 6s²
Where,
s = side length
Cube X has a side length of 1,
Surface area of cube, X = 6s²
= 6 * 1²
= 6 * 1
= 6
cube Y has a side length of 2
Surface area of cube, Y = 6s²
= 6 * 2²
= 6 * 4
= 24
How much greater is the surface area of cube Y than cube X?
Surface area of Cube Y is 3 times greater than the surface area of cube X
Sum of the terms of the series is
Sn = n/2 ( a1+an )
we have n= 6 , a1= 17, an = 57
so Sn = 6/2 ( 17+57) = 3(74) = 222
Answer:
w ≥ 6
l ≥ 11
Step-by-step explanation:
The perimeter of a rectangle is equal to P = 2l+2w where l=length and w=width. Here the length is 5 feet longer than the width or 5+w. This means the width is w. Substitute P = 34, l=5+w and w into the perimeter equation. Then solve for w.
34 ≤ 2*(5+w) + 2w
34 ≤ 10+2w+2w
34 ≤ 10+4w
24 ≤ 4w
6 ≤ w
This means the width must be at least 6 so the solution is w ≥ 6.
To find the length substitute 6 into l ≤ 5+w.
l ≤ 5 + 6
l ≤ 11
The length is l ≥ 11.
Answer:
I believe this is neither a direct or inverse relationship.
Step-by-step explanation: