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vichka [17]
2 years ago
10

What is 10 ÷ 2/5 (show ur work) THANKS

Mathematics
2 answers:
givi [52]2 years ago
5 0

Answer:

10 \div \displaystyle{ \frac{2}{5} }

\displaystyle{ \frac{1}{10}  \times  \frac{5}{2} }

\displaystyle{ \frac{1}{ \cancel{10} {}^{2} } \times  \frac{5}{2}  }

\displaystyle{ \frac{5}{4} }

\displaystyle{1 \frac{1}{4} }

slamgirl [31]2 years ago
3 0
Hope this helps! Good luck!

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galina1969 [7]

Answer:

The rate of change or slope m  = -50

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the rate of change or slope
  • b is the y-intercept

Given that there is $500 in Holly's bank account.

Thus, the y-intercept b = 500

It is stated that she takes out $50 from her account each month but doesn't put money back in.

It means the rate of change or slope is decreasing.

Thus, the rate of change or slope m  = -50

<u>EXTRA BONUS!</u>

We can also determine the line equation by substituting m = -50 and b = 500 in the slope-intercept form

y = mx+b

y = -50x + 500

Here:

The slope m = -50

The y-intercept = 500

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3 years ago
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MAXImum [283]
I know one would be NQ=KL the rest you got it boss✊
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Can one angle of a parallelogram be equal to 40° and another one 50°? Justify your reasoning.
Dahasolnce [82]
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If the two are one after another, then they are not supplementary, which a parallelogram requires.

If they are in opposite corners, they must be equal. That's another property of parallelograms.
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spayn [35]

Answer: Option d.

Step-by-step explanation:

It is important to remember the following proporties in order to solve the exercise:

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In this case you have this expression given in the exercise:

ln(\sqrt{xy})+ln(\frac{x}{e})

Since equivalent expression have always the same value, you can simplify the expression given in order to find an equivalent expression.

Therefore, applying the corresponding properties, you get the following equivalent expression (Remember that \sqrt[n]{a^n}=a):

ln(\sqrt{xy})+ln(\frac{x}{e})=ln(\sqrt{xy})+ln(x)-ln(e)=ln(x\sqrt{xy})-1

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