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3 years ago

Find the number of terms in this polynomial. -5h + 8

Mathematics

1 answer:

Arisa [49]3 years ago

4 0

Hi! I can help you with joy! :)

Let's find the number of terms in this polynomial.
The given polynomial has 2 terms:
-5h and 8
Polynomials with 2 terms are called "binomials"
Thus, -5h+8 has 2 terms.

<u>Answer:</u>

2 terms

Hope it helps!

$\rm{Stargazing{\bold{WithJoy:D}$

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8/6 20/x the figures are similar find x

Lana71 [14]

The process:

8/6 = 20/x

You would have to cross multiply first.

8 20 6×20= 120
6 x 8×x=8x

Then you rearrange the equation,

120=8x

And you divide by 8 ( because it has the variable next to it)

120÷8=15

So, x=15

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3 years ago

The ages of a random sample of five university professors are 39, 54, 61, 72, and 59. Using this information, find a 99% confide

blsea [12.9K]

Answer:

$38.898 \leq \sigma^2 \leq 2792.356$

Now we just take square root on both sides of the interval and we got:

$6.237 \leq \sigma \leq 52.843$

Step-by-step explanation:

Data given and notation

34,59,61,71,59

We can calculate the sample standard deviation with the following formula:

$s^2= \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$s= \sqrt{s^2}$

s=12.021 represent the sample standard deviation

$\bar x$ represent the sample mean

n=5 the sample size

Confidence=99% or 0.99

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=5-1=4$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.005,4)" "=CHISQ.INV(1-0.005,4)". so for this case the critical values are:

$\chi^2_{\alpha/2}=14.860$

$\chi^2_{1- \alpha/2}=0.207$

And replacing into the formula for the interval we got:

$\frac{(4)(12.021)^2}{14.860} \leq \sigma^2 \leq \frac{(4)(12.021)^2}{0.207}$

$38.898 \leq \sigma^2 \leq 2792.356$

Now we just take square root on both sides of the interval and we got:

$6.237 \leq \sigma \leq 52.843$

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Answer: a one-way ANOVA

Step-by-step explanation:

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OlgaM077 [116]

x*7=14

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Answer:

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Find the number of terms in this polynomial. -5h + 8​

Find the number of terms in this polynomial. -5h + 8