Answer:.
Step-by-step explanation:
Answer:
The middle terms do not take into ........
Speed = distance/time
distance = speed * time
let x = time covered by running
15 = run distance + walk distance
15 = 9(x) + 3(3-x)
15 = 9x + 9 - 3x
15 - 9 = 6x
6 = 6x
x = 1 hour
Therefore:
Running distance = speed * time
RD = 9km/hr * 1 hr
RD = 9km
We know that Scott has put 6 rows with 5 stickers each.
The total number of stickers available with Scott = 5*6 = 30 stickers
These 30 stickers are now placed in 5 rows with equal number of stickers in each row.
Number of stickers in each row= Total number of stickers available/number of rows
Number of stickers in each row = 30/5 = 6 stickers
Number of stickers in each row now would be = 6 stickers
Answer:
The rate of change of the distance between the cars at that instant is 5.46 meters per second
Step-by-step explanation:
Speed of first car = 7 m/s
Speed of second car = 3 m/s
At instant, distance of first car from intersection = 5 meters
distance of second car from intersection = 12 meters
Therefore, we have
Distance between both cars at intant = √(12² + 5²) = 13 m
Rate of cahnge of distance is given by;
2ddd/dt = d(x² + y²)/dt = 2xdx/dt + 2ydy/dt
= 26dd/dt = 2×5×7 + 2×12×3 = 142
dd/dt = 142/26 = 5.46 m/s.
That is the rate of change of the distance between the cars at that instant = 5.46 meters per second.