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2 years ago

Find the geometric mean of 4 and 49

Mathematics

1 answer:

Paraphin [41]2 years ago

4 0

The geometric mean of 4 and 49 is 14

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What is Bc and what is ac

dolphi86 [110]

Answer:

Before and after current era

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3 years ago

Matthew scored a total of 168 points in basketball this season. He scored 21 points in his only playoff ganie. What percent of h

SSSSS [86.1K]

You do 168+21=189 then you work out what 189 is as % so your answer =18900%

6 0

3 years ago

The diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm. How much bigger is the distance around a quarter

olga55 [171]

Answer:

9.577 mm.

Step-by-step explanation:

We have been given that the diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm.

Let us find the circumference of quarter and nickel using circumference of circle formula.

$\text{Circumference of circle}=2\pi r$ , where r represents radius of the circle.

Since we know that diameter of circle is 2 times its radius, so let us find radius of quarter and nickel by dividing their diameter by 2.

$\text{Radius of quarter}=\frac{24.26}{2}$

$\text{Radius of quarter}=12.13$

$\text{Radius of nickel}=\frac{21.21}{2}$

$\text{Radius of nickel}=10.605$

$\text{Circumference of quarter}=2\times 3.14\times 12.13$

$\text{Circumference of quarter}=76.1764$

Therefore, circumference of quarter is 76.1764 mm.

Let us find circumference of nickel.

$\text{Circumference of nickel}=2\times 3.14\times 10.605$

$\text{Circumference of nickel}=66.5994$

Let us subtract circumference of nickel from circumference of quarter.

$\text{The difference between distance around quarter and nickel}=76.1764-66.5994$

$\text{The difference between distance around quarter and nickel}=9.577$

Therefore, the distance around a quarter is 9.577 millimeters bigger than a nickel.

7 0

4 years ago

Find the angle between the given vectors to the nearest tenth of a degree.

Bond [772]

Answer:

Step-by-step explanation:

If θ is the angle between two vectors u and v, then cosθ = (u·v) / [llull llvll]

u·v = (8)(9) + (7)(7) = 121

llull = √[(8)2 + (9)2] = √145 llvll = √[(7)2+(7)2] = 7√2

So, cosθ = 121/ [7√290]

= 1.015052094

θ = Cos-1(1.015052094) ≈ 3.3

6 0

3 years ago

After 5 months, the number of subscribers to a newspaper was 5,730. After 7 months, the number of subscribers to the newspaper w

Yuki888 [10]

(5,5730) (7,6022)
slope = (6022 - 5730) / (7 - 5) = 292/2 = 146

y = mx + b
slope(m) = 146
(5,5730)...x = 5 and y = 5730
sub and find b, the y int
5730 = 146(5) + b
5730 = 730 + b
5730 - 730 = b
5000 = b

so ur equation is : y = 146x + 5000 <==

3 0

3 years ago