Question

Two forces, F1 and F2, are acting on a body, as shown in the figure. The resultant force, R= ?, is newtons.

Answer 1

I hope this helps u....

Answer 2

Answer:

R ,is the Resultant of two forces, $F_{1},F_{2}$

∠ACB +50°=180°

∠ACB=180° -50°

∠ACB=130°

$R^{2} =[F_{1}]^2+[F_{2}]^2-2\times F_{1}\times F_{2} \times \cos(\angle ACB )\\\\R^2=(40)^2 +(38)^2-2 \times 40 \times 38 \cos(\angle 130 ^{\circ})\\\\R^2=1600+1444-3040\times (-0.6427)\\\\ R^2=3044+1953.808\\\\ R^2=4997.808\\\\R=70.695$

→Cos(130°)=Cos (180°-50°)= -cos 50°= -0.6427

Magnitude of resultant force =70.70 Newtons(Approx)