Answer:
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
Step-by-step explanation:
Volume of the Cylinder=400 cm³
Volume of a Cylinder=πr²h
Therefore: πr²h=400
Total Surface Area of a Cylinder=2πr²+2πrh
Cost of the materials for the Top and Bottom=0.06 cents per square centimeter
Cost of the materials for the sides=0.03 cents per square centimeter
Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)
C=0.12πr²+0.06πrh
Recall:
Therefore:
The minimum cost occurs when the derivative of the Cost =0.
r=3.17 cm
Recall that:
h=12.67cm
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
Answer:
33π FT^2
Step-by-step explanation:
A=πr(r+(h2+r2)^1/2)
= π3(3+8)
=33π
On the unit circle the hypotenuse is always one so we can say:
sinα=y/1 and cosα=x/1 so
The point corresponding the the angle 600° is:
(cos600, sin600) which is approximately
(-1/2, -√(3/4)
<u>Given</u>:
A rhino runs at a speed of about 28 miles per hour.
We need to determine the speed in feet per second.
<u>Converting miles to feet:</u>
The miles can be converted to feet by multiplying 5280 with 28 miles per hour.
Thus, we have;
Thus, the speed of the rhino in feet per hour is 147840
<u>Converting hours to seconds:</u>
The hours can be converted into seconds by dividing 147840 by 3600 (Because an hour has 60 seconds in a minute and 60 minutes in an hour)
Thus, we get;
Rounding off to the nearest whole number, we get;
Therefore, the speed of the rhino is 41 feet per second.
Hence, Option B is the correct answer.
