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musickatia [10]
3 years ago
12

The letter A indicates _____. lateral meristem secondary xylem apical meristem vascular cambium cork cambium

Biology
1 answer:
il63 [147K]3 years ago
5 0

The secondary xylem is produced by the cambium. It is placed between the cambium and the medulla. Option B is correct. Secondary xylem.

<h3>What is the secondary xylem?</h3>

The secondary xylem is the tissue that proceeds from the vascular cambium activity.

Its cells are orientated in different ways composing the vertical/axial system and the horizontal/transversal system.

The secondary xylem is essential to the tree growth in high because of its resistance and the capacity to transport water long distances.

Secondary xylem functions are to transport water and minerals through its vessels and tracheids, to provide support and resistance to the plant, and to store reserve substances.

In the cross-section of the adult tree trunk,

  • The outermost layer that interacts with the environment is called periderm (Brown Layer).

  • The second layer that follows the periderm is the phloem (Layer C).

  • The next layer is the cambium (lateral meristem), which produces phloem cells and xylem cells (Layer B).

  • The secondary xylem follows the vascular cambium (Layer A), and

  • The medulla is located in the centre of the trunk.

Letter A indicates the <u>secondary xylem</u>.

You will learn more about the secondary xylem at

brainly.com/question/790747

brainly.com/question/15035852

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During both mitosis and meiosis, DNA replicates first during S phase of interphase. Each copy (DNA molecule) is called chromatid. Before anaphase they remain together, joined by the centromere in the chromosome.

Part 1: How many chromatids and chromosomes are present at:

(a) anaphase of mitosis: During this phase sister chromatids split. We would have 48 chromosomes in each pole and 48 chromatides.

(b) anaphase I of meiosis: During this phase homologous chromosomes split, being a reductional division. In each pole we will have half the chromosomes we had after DNA replication. This is 24 chromosomes but 48 chromatides (remember they will split during anaphase II).

(c) anaphase II of meiosis: This is an equational division, we will have 24 chromosomes in each pole and 24 chromatides. Each chromatid is considered a chromosome.

(d) G1 prior to mitosis: During this phase DNA has not replicated yet and it is not condensed either. This formed is called chromatin. We will assign one chromatid for each chromosome. This is a somatic cell, so: 48 chromosomes and 48 chromatids.

(e) G2 prior to mitosis: After S phase, we have duplicated all chromosomes. We will assign two chromatids per chromosome: this is 96 chromatides and 48 chromosomes.

(f) G1 prior to meiosis: Before DNA duplication, 48 chromosomes, 48 chromatids.

(g) Prophase of meiosis I: After DNA replication, condensation of the chromatin takes place: 48 chromosomes, 96 chromatids.

Part 2: How many chromatids or chromosomes are present in:

(h) An oogonial cell prior to S phase: This is G1 phase, 48 chromosomes.

(i) A spermatide: This is the male haploid gametid, after meiosis: 24 chromosomes and 24 chromatids.

(j) A primary oocyte arrested prior to ovulation: They are arrested at prophase I of meiosis. This means their DNA is still duplicated and chromatides have not divided yet. 48 chromosomes and 96 chromatids.

(k) A secondary oocyte arrested prior to fertilization: They are halted at metaphase II of meiosis, meaning they have half the chromosomes (24) but chromatids are still together (48).

(l) A second polar body: They suffered the same process as the mature ovum but remained with little cytoplasm. They have 24 chromosomes and 24 chromatids.

(m) A chimpanzee sperm: They have completed both meiosis as well, they have 24 chromosomes and 24 chromatids.  

Explanation:

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