Answer:
5, 15, 45 and 135
Step-by-step explanation:
Given the recursive function;
an = 3a(n-1)
If a1 = 5
a2 = 3a1
a2 = 3(5)
a2 = 15
For a3;
a3 = 3a2
a3 = 3(15)
a3 = 45
For a4;
a4 = 3a3
a4 = 3(45)
a4 = 135
Hence the first four terms are 5, 15, 45 and 135
1.
None
2.
Student 2
<span>Know the answer? Add it here!</span>3.
Student 1 and student 3
4.
None
5.
Student 1
Disclaimer: I'm not 100percent sure, but I'm pretty sure
Hope this helps!
Answer:
16-(4*x)-(4*x^2)+x^3
Step-by-step explanation:
(x+2)(x-2)(x-4)
16-(4*x)-(4*x^2)+x^3