Question

B r u h. Just help for points. No answer no points

Answer 1

Answer:

$\left(-34, \dfrac{33}{2}\right)$

Step-by-step explanation:

Create a linear equation for line AB and line CD

Find slope using slope formula $m=\dfrac{y_2-y_1}{x_2-x_1}$

then use point-slope form of linear equation $y-y_1=m(x-x_1)$

(where m is the slope and $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line)

Line AB

$m=\dfrac{-16+1}{-8+20}=-\dfrac54$

$\implies y+1=-\dfrac54(x+20)\\\\\implies y=-\dfrac54x-26$

Line CD

$m=\dfrac{0+11}{-19+9}=-\dfrac{11}{10}$

$\implies y+11=-\dfrac{11}{10}(x+9)\\\\\implies y=-\dfrac{11}{10}x-\dfrac{209}{10}$

To find the point of intersection, equate the equations and solve for x::

AB = CD

$\implies -\dfrac54x-26=-\dfrac{11}{10}x-\dfrac{209}{10}$

$\implies -\dfrac{3}{20}x=\dfrac{51}{10}$

$\implies x=-34$

Substitute found value of x into one of the equations and solve for y:

$y=-\dfrac54(-34)-26=\dfrac{33}{2}$

Therefore, point of intersection is  $\left(-34, \dfrac{33}{2}\right)$