An integer is 5 more than 4 times another. If the product of the two integers is 51, then find the integers.
1 answer:
Answer:
<u>3 </u> <u>and</u> <u> 17</u> are required integers
Step-by-step explanation :
Let one integer be x And other integer be y
x = 4y + 5
xy = 51
<u>According to </u> <u>question </u> <u>:</u>
➞ (4y + 5)y = 51
➞ 4y² + 5y = 51
➞ 4y² + 5y - 51 = 0
➞ 4y² + 17y - 12y - 51 = 0
➞ y (4y + 17) - 3(4y + 17) = 0
➞ (y - 3)(4y - 17) = 0
➞ y - 3 = 0
➞ <u>y = 3</u>
Hence ,
➞ <u>y = 3</u>
➞ x = 4y + 5
➞ x = 4 (3) + 5
➞ x = 12 + 5
➞<u> </u> <u>x = 17</u>
∴ The required integers are <u>3 and 17</u>
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