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Pavel [41]
2 years ago
15

An integer is 5 more than 4 times another. If the product of the two integers is 51, then find the integers.

Mathematics
1 answer:
Yakvenalex [24]2 years ago
7 0

Answer:

  • <u>3 </u><u>and</u><u> 17</u> are required integers

Step-by-step explanation:

  • Let one integer be x
  • And other integer be y

x = 4y + 5

xy = 51

<u>According to </u><u>question </u><u>:</u>

➞ (4y + 5)y = 51

➞ 4y² + 5y = 51

➞ 4y² + 5y - 51 = 0

➞ 4y² + 17y - 12y - 51 = 0

➞ y (4y + 17) - 3(4y + 17) = 0

➞ (y - 3)(4y - 17) = 0

➞ y - 3 = 0

➞ <u>y = 3</u>

Hence,

➞ <u>y = 3</u>

➞ x = 4y + 5

➞ x = 4 (3) + 5

➞ x = 12 + 5

➞<u> </u><u>x = 17</u>

∴ The required integers are <u>3 and 17</u>

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FinnZ [79.3K]
<h3>Answer: (c * d)(x) = 4x^3 + 18x^2 - 10x</h3>

Work Shown:

I'm assuming the dot means multiplication. If so, then,

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