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s344n2d4d5 [400]
2 years ago
5

The length and the width of a rectangle are in the ratio of 5 to 2, and the area is 1,000 sq. ft. Find the dimensions.

Mathematics
1 answer:
sleet_krkn [62]2 years ago
8 0

Step-by-step explanation:

l = length

w = width

l/w = 5/2

l = 5w/2

l×w = 1000ft²

(5w/2)×w = 1000

5w²/2 = 1000

5w² = 2000

w² = 400

w = 20ft

l = 5w/2 = 5×20/2 = 5×10 = 50ft

the length is 50ft.

the width is 20ft.

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s344n2d4d5 [400]

Answer:

a). Mileage for carA= \frac{2}{x}  , and mileage for carB=\frac{ 3x+2}{x(x+1)}

b).total mileage for both is similar to average of them= \frac{(mileageA + mileageB)}{2}

=\frac{5x+4}{2x(x+1)}[tex]mil/gal

Step-by-step explanation:

It is given that the distance traveled by car A=2x+2=2(x+1)

And distance traveled by car B= 3x+2

We know the mileage is mile/gallon,

a).So mileage of car A= \frac{distance traveled by car A}{gallos of fuel used}

=\frac{2x+2}{x^2 +x}\\ =\frac{2(x+1)}{x(x+1)} \\=\frac{2}{x}mil/gal

Similarly , the mileage for car B= \frac{distance traveled by car A}{gallons of fuel used}

=\frac{3x+2}{x^2+x} \\=\frac{3x+2}{x(x+1)}mil/gal

b).total mileage for both is similar to average of them= \frac{(mileageA + mileageB)}{2}

=\frac{2x+2}{x(x+1)}+\frac{3x+2}{x(x+1)}\\ =\frac{2x+2+3x+2}{x(x+1)}\\=\frac{5x+4}{x(x+1)}mil/gal

Now divide by 2 for total(average) mileage.

\frac{\frac{5x+4}{x(x+1)} }{2}\\ =\frac{5x+4}{2x(x+1)} mil/gal.

Thus those are the answers.

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The amount of chlorine in a swimming pool is proportional to the volume of water. The pool has 2.5 milligrams of chlorine per li
stira [4]

Answer:

There are <u>20,000 milligrams</u> chlorine in the pool.

Step-by-step explanation:

Given:

The chlorine per liter of water in the pool is 2.5 milligrams.

The  volume of water in the swimming pool is 8000 gallons.

Now, to find the quantity of chlorine in the pool.

Let the quantity of chlorine be x.

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The milligrams of chlorine per liter of water in the pool = 2.5.

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