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Ksenya-84 [330]
2 years ago
8

HELP! Read the comments. 5w–10>20 ; with the given set → {5,6,7,8} its for an assignment

Mathematics
2 answers:
Greeley [361]2 years ago
8 0

Answer:

w>6

5w−10>20

Add 10 to both sides.

5w>20+10

Step-by-step explanation:5w>20+10

Add 20 and 10 to get 30.

5w>30

Divide both sides by 5. Since 5 is positive, the inequality direction remains the same.

w>

5

30

​

Divide 30 by 5 to get 6.

I think

valentinak56 [21]2 years ago
4 0

Answer:

w = 7, and w = 8 is correct

Step-by-step explanation:

1. Why 5 does not work

<u>a. Substitute 5 into the equation</u>

5w-10>20 --> 5(5) - 10 > 20

<u>b. Solve the equation</u>

Remember Pemdas:

P- Parentheses First

E- Exponents Second

M- Multiplication Third

D- Division Fourth

A- Addition Fifth

S- Subtraction Sixth

We are not working with Exponents and Parentheses, but we are working with the rest.

Since there is no P and E, that means that multiplication is first

5(5)-10>20 - 5(5) = 5 x 5 = 25

Now all is left is to subtract:

25 - 10 = 15

15 > 20 Is not true.

2. Why 6 does not work

<u>a. Substitute</u>

5w-10>20 --> 5(6) - 10 > 20

<u>b. Solve</u>

5(6) = 5 x 6 = 30

30 - 10= 20

20 > 20 is not true

Just like you are not greater than yourself, 20 can not be greater than its own self.

3. Why 7 and 8 work (7a, 7b is 7; 8a, 8b is 8)

<u>7a. </u>Substitute

5w-10>20 --> 5(7) - 10 > 20

<u>8a. </u>Substitute

5w - 10 >20 --> 5(8) - 10 > 20

<u>7b. </u> Multiply and subtract

5(7) = 5 x 7 = 35

35 - 10 = 25

25 > 20

25 is greater than 20

<u>8b. </u>Multiply

5(8) = 5 x 8 = 40

40 - 10 = 30

30 > 20

30 is greater than 20

Hereby, w = 7, and w = 8

Hope this helps

-jp524

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ser-zykov [4K]

The right step followed in the system to get he equations is (D). To get the system B. The second equation in system A was replaced by the sum of that equation and the first equation multiplied by 6. The solution to system B will be the same as the solution of system A.

<h3>Meaning of Simultaneous Equation.</h3>

A simultaneous equation can be defined as an equation that possesses two unknowns and one constant.

The solution to the problem can only be gotten by solving it side by side with another equation of the same format.

In conclusion, The right step followed in the system to get he equations is (D). To get the system B. The second equation in system A was replaced by the sum of that equation and the first equation multiplied by 6. The solution to system B will be the same as the solution of system A.

Learn more about simultaneous equation: brainly.com/question/148035

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1 year ago
A kindergarten class has 9 girls and 11 boys in class.What percent of the class are girlsit rain
Nesterboy [21]
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3 years ago
How many solutions y= -2x -4 and y=3x plus 3
Oksi-84 [34.3K]

Answer:

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2 years ago
Identify the solutions to the quadratic equation 6x^2+x-1=0
tigry1 [53]

Answer:

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Step-by-step explanation:

You can use the factoring method to identify the solutions of x

6x^2+x-1

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So, you get 3x and 2x

since you know that -1x1 is -1 you will get

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5 0
1 year ago
(x-1)(x-3)(x+5)(x+7)=297
mihalych1998 [28]

First simplify the expression into polynomial form,

(x-1)(x-3)(x+5)(x+7)=297

x^4+8x^3-10x^2-104x+105=297

x^4+8x^3-10x^2-104x-192=0

Now factor into,

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Which means the solutions are,

x-4=0\implies\boxed{x_1=4}

x+8=0\implies\boxed{x_2=-8}

and then two complex solutions because determinant of the third factor D\lt0,

x^2+4x+6=0

x^2+4x+4=-2

(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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