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Tomtit [17]
3 years ago
11

Once goals and objectives are clearly defined, what should a successful company do next in its content strategy?

Computers and Technology
2 answers:
Usimov [2.4K]3 years ago
8 0

Answer:

An effective Content Marketing strategy must have four core elements to be successful: brand positioning, owned media value proposition, business case, and strategic plan. Let's see why these elements are essential for Content Marketing and how you can start implementing each of them.

Explanation:

mark me as brainlist..

elena55 [62]3 years ago
8 0

Answer:

To work hard for the work to excel

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It is a group of two or more computer system connect to each other​
Sedbober [7]

network is a group of two or more computer system connected together

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Which of these devices can completely stop broadcasts from being passed on across the network? routerswitchaccess ponthub
cestrela7 [59]

Answer

An Access point can completely stop broadcasts from being passed on across the network.

Explanation.

An Access point is a hardware type that is part of local area network which has capability of allowing wireless communication from devices through a wireless stand,which connects in between devices and the network. A good example of these devices are routers that allows wireless devices to connect to a wireless network.So when it is passed on across a network an Access point can completely stop.

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3 years ago
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Write a C++ program that searches for anagrams in a dictionary. An anagram is a word obtained by scrambling the letters of some
Semmy [17]

Answer:

d, avt, car, feet, more, pitch, rome, tac, teef,

Anagrams of b in dictionary

Anagrams of cat in dictionary

avt, cat, tac,

Anagrams of room in dictionary

more, rome,

Anagrams of hello in dictionary

Anagrams of  in dictionary

Explanation:

// FindAnagrams.cpp : it is the starting point of application console.

//

#include <vector>

#include <hash_map>

#include <iostream>

#include <string>

#include <algorithm>

#include <map>

#include <set>

using namespace std;

using namespace stdext;

bool IsAnagrams(string& strA, string& strB)

{

   list<char> listA(strA.begin(), strA.end());

   list<char> listB(strB.begin(), strB.end());

   listA.sort();

   listB.sort();

   return listA == listB;

   // return equal(listA.begin(), listA.end(), listB.begin());

}

string SortChars(string str)

{

   list<char> l(str.begin(), str.end());

   l.sort();

   return string(l.begin(), l.end());

}

set<string> FindAnagrams(list<string>& dict, string findStr)

{

   map<string, set<string>> d;

   typedef pair<string, set<string>> MyPair;

   for(list<string>::const_iterator it = dict.begin(); it != dict.end(); ++it){

       string str(SortChars(*it));

       if(d.find(str) == d.end()){

           set<string> s;

           s.insert(*it);

           d.insert(MyPair(str, s));

       }

       else{

           d[str].insert(*it);

       }

   }

   string sortedStr(SortChars(findStr));

   return d[sortedStr];

}

int main(int argc, char* argv[])

{

   list<string> dict;

   dict.push_back("c");

   dict.push_back("car");

   dict.push_back("avt");

   dict.push_back("taac");

   dict.push_back("feet");

   dict.push_back("teef");

   dict.push_back("rom");

   dict.push_back("more");

   dict.push_back("pit");

   dict.sort();

   cout << "The dictionary: " << endl;

   copy(dict.begin(), dict.end(), ostream_iterator<string>(cout, ", "));

   cout << endl;

   list<string> testCases;

   testCases.push_back("d");

   testCases.push_back("car");

   testCases.push_back("rome");

   testCases.push_back("hell");

   testCases.push_back("");

   for(list<string>::iterator it = testCases.begin(); it != testCases.end(); ++it)

   {

       cout << endl << "Anagrams of " << *it << " in dictionary" << endl;

       set<string> output = FindAnagrams(dict, *it);

       copy(output.begin(), output.end(), ostream_iterator<string>(cout, ", "));

       cout << endl;

   }

   return 0;

}

8 0
3 years ago
Design a program takes as input, X, an unsorted list of numbers, and returns the sorted list of numbers in X. The program must b
Lelechka [254]

Answer:

The program in python is as follows:

def split(X):

   L = []; G = []

   for i in range(len(X)):

       if X[i]>=X[0]:

           G.append(X[i])

       else:

           L.append(X[i])

   L.sort(); G.sort()

   return L,G

X = []

n = int(input("Length of X: "))

for i in range(n):

   inp = int(input(": "))

   X.append(inp)

   

if len(X) == 0 or len(X) == 1:

   print(X)

else:

   X1,X2=split(X)

   newList = sorted(X1 + X2)

   print(newList)

Explanation:

The following represents the split function in the previous problem

def split(X):

This initializes L and G to empty lists

   L = []; G = []

This iterates through X

   for i in range(len(X)):

All elements of X greater than 0 equal to the first element are appended to G

      <em> if X[i]>=X[0]:</em>

<em>            G.append(X[i])</em>

Others are appended to L

<em>        else:</em>

<em>            L.append(X[i])</em>

This sorts L and G

   L.sort(); G.sort()

This returns sorted lists L and G

   return L,G

The main function begins here

This initializes X

X = []

This gets the length of list X

n = int(input("Length of X: "))

This gets input for list X

<em>for i in range(n):</em>

<em>    inp = int(input(": "))</em>

<em>    X.append(inp)</em>

This prints X is X is empty of has 1 element

<em>if len(X) == 0 or len(X) == 1:</em>

<em>    print(X)</em>

If otherwise

else:

This calls the split function to split X into 2

   X1,X2=split(X)

This merges the two lists returned (sorted)

   newList = sorted(X1 + X2)

This prints the new list

   print(newList)

7 0
3 years ago
Sharon reads two different articles about avocados. The first article, in a weight loss magazine, claims that avocados are unhea
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The first and third.
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3 years ago
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