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deff fn [24]
2 years ago
15

BRAINLIEST PLEASE ANSWER FAST THIS IS MY SECOND TIME REPOSTING THIS I WILL GIVE BRAINLIEST!

Mathematics
2 answers:
Alekssandra [29.7K]2 years ago
7 0

Kind note:

I am sure that the triangle you meant was in the image attached. I will find n in the image I attached.

Solution:

<u>We know that:</u>

  • ∠B = 90°
  • ∠A = 38°
  • Sum of interior angles of a triangle = 180°

<u>Step-1: Find ∠C.</u>

  • ∠A + ∠B + ∠C = 180°
  • => 38 + 90 + ∠C = 180°
  • => ∠C + 128 = 180°
  • => ∠C = 180 - 128 = 52

<u>Step-2: Find n.</u>

52 and n are a linear pair.

  • 52 + n = 180
  • => n = 180 - 52
  • => n = 128

damaskus [11]2 years ago
3 0
52 degrees

180 degrees is the total “degree value” of a triangle

90 degrees is given because the triangle is a right triangle

38 degrees is given as angle A

180 - 90 - 38 = 52 degrees
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The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
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Answer:

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Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

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Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


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3 years ago
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