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2 years ago

Simplify the exponential problem 7b^5/b^4

Mathematics

2 answers:

fredd [130]2 years ago

6 0

7b is the simplified answer

Norma-Jean [14]2 years ago

5 0

Solution:

If the numerator and the denominator have like bases in exponents, then the exponents subtract.

$\frac{7b^5}{b^4} = 7b^5^{-4}$
=> $7b$

Thus, 7b is the simplified expression.

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Help Please!!!!!!!!!!

LenKa [72]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$x+3y\leq 6$

Isolate the variable y

$3y\leq 6-x$

$y\leq 2-(1/3)x$

The solution is the shaded area below the solid line

Is below because the symbol of the inequality is less

Is a solid line because the line is included in the solution

The equation of the solid line is $y=2-(1/3)x$

To graph the solution find the intercepts

Find the x-intercept (value of x when the value of y is equal to zero)

For y=0, x=6 --------> point (6,0)

Find the y-intercept (value of y when the value of x is equal to zero)

For x=0, y=2 -------> point (0,2)

Graph the inequality

see the attached figure

5 0

2 years ago

There are 3 types of gummy bears:

mr Goodwill [35]

Using proportions, it is found that it takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

10 mini-bears weights to 12.1 grams, hence the weight of a mini-bear is of:

12.1/10 = 1.21 grams.

10 regular bears weights to 23.1 grams, hence the weight of a regular bear is of:

23.1/10 = 2.31 grams.

1 super bear weights to 2250 grams, hence the proportion between the weight of a super bear and the weight of a mini-bear is:

2250/1.21 = 1860.

The proportion between the weight of a super bear and the weight of a regular bear is:

2250/2.31 = 974.

The difference of proportions is given by:

1860 - 974 = 886.

It takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

5 0

4 months ago

2. John earns a 3% commission for every car he sells. Today he sold a car for $13,600. How much commission did he receive? (To f

OlgaM077 [116]

Answer:

$408

Step-by-step explanation:

Find 3% of $13,600:

3 * 13,600 / 100 = $408

7 0

2 years ago

Which of the following would be considered a monomial? Select all that apply

Vaselesa [24]

Answer:

A and B

Step-by-step explanation:

Since these both only have one term and number/variable, making it a monomial.

4 0

2 years ago

If this angle is 1/6 of a rotation about a circle, then its measure is

Nezavi [6.7K]

Answer:

60 degrees.

Step-by-step explanation:

A full rotation is 360 degrees.

So 1/6 is 360 * 1/6 = 60 degrees.

4 0

2 years ago