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MissTica
2 years ago
8

if a town with a population of 500 doubles in size ever 9 years, what will the population be 36 years from now?

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
4 0

The population of the town in 36 years would be  8000.

<h3>What would be the population of the town in 36 years?</h3>

The formula that can be used to determine the town's population is:
FV = P (1 + r)^n

Where:

  • FV = Future value
  • P = Present value
  • R = rate of growth = 100%
  • N = number of years = 36/9 = 4

500 x 2^4 = 8000

To learn more about future value, please check: brainly.com/question/18760477

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Y=fx) = 8x<br> Find f(x) when x = 1/3<br> Enter the correct answer.
solniwko [45]

Answer:

f(3)=2\frac{2}{3}

Step-by-step explanation:

f(x)=8x\\f(3)=8(\frac{1}{3})\\f(3)=\frac{8}{3} \\f(3)=2\frac{2}{3}

Hope this helps!

4 0
3 years ago
Find a solution to the following system of equations.
Nina [5.8K]

Answer:

A. \displaystyle (2, 5)

Step-by-step explanation:

Plugging these coordinates into the system of equations will give you these genuine statements:

\displaystyle -10 + 5 = -5 \\ -8 + 10 = 2☑

I am joyous to assist you anytime.

4 0
3 years ago
If 10% of a number is 8, what is 50% of the number?
Over [174]

Answer:

50% of the number is 40

Step-by-step explanation:

8 * 5 = 40

7 0
3 years ago
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Machine A can fill an order of widgets in a hours. Machine B can fill the same order of widgets in b hours. Machines A and B beg
ycow [4]

Answer:

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Step-by-step explanation:

Consider the provided information.

Machine A can fill an order of widgets in a hours. Machine B can fill the same order of widgets in b hours.

Thus, in 1 hr machine A's work is 1/a and machine B's work is 1/b.

We need to find whether the Machine A's rate the same as that of Machine B?

Statement 1: Machines A and B finish the order at exactly 4:48 p.m.

Total time, A and B worked = 4:48 = 4+\frac{48}{60} hrs = 4+\frac{4}{5} hrs= \frac{24}{5} hours

Thus, \frac{1}{a}+\frac{1}{b} = \frac{5}{24}

Let say Machine A's rate the same as that of Machine B

\frac{1}{a}+\frac{1}{a} = \frac{5}{24}\\\\\frac{2}{a} = \frac{5}{24}\\\\a = \frac{48}{5}

It is given that a and b are even integers, but \frac{48}{5} is not an even integer.

Hence, Machine A's rate is not same as that of Machine B.

Therefore, statement (1) ALONE is sufficient.

Statement 2: (a + b)^2 = 400

(a+b)^2 = 400\\a+b=20

There are many possible case in which a and b are even integer and there sum is 20.

If a = b = 10 (both even), then Machine A's rate is same as that of Machine B.

if a = 6 and b = 14 (both even), then Machine A's rate is not same as that of Machine B.

Therefore, No unique answer with statement 2.

Hence, statement 2 alone is not sufficient.

6 0
3 years ago
1. True False 3(2 + 4) = 3 x 2 + 4
Gnoma [55]

Answer:

1. False

2. True

3. False

4. True

5. True

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