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morpeh [17]
3 years ago
8

+1) -4x = 5-(x-3)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

x=\frac{-1}{6}

Step-by-step explanation:

9(x+1) -4x = 5-(x-3)

9(x+1) -4x = 5-(x-3) \\

9x+9\cdot1-4x=5-\left(x-3\right)

9x+9-4x=5-\left(x-3\right)

\left(9x-4x\right)+9=5-\left(x-3\right)

5x+9=5-\left(x-3\right)

5x+9=5-x+3

5x+9=-x+\left(5+3\right)

5x+9=-x+8

5x+9=-x+8

5x+9+x=-x+8+x

5x+x+9=-x+8+x

6x+9=-x+8+x

6x+9=-x+x+8

6x+9=8

6x+9=8

6x+9-9=8-9

6x=8-9

6x=-1

\frac{6x}{6}=\frac{-1}{6}

x=\frac{-1}{6}

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The leftmost digits of rwo nunbers are 8 and 3 which one is greater
makvit [3.9K]
EIGHT WOULD BE GREATER

7 0
3 years ago
The weight of an object is equal to 3\4 of its own weight plus 3\4of a pound. What is the weight?
Phoenix [80]

Answer:

The weight of the object is 3 kg.

Step-by-step explanation:

<u>Step 1: </u>

Let object weight be x kg.

Now, as per the available data,

3/4 kg + 3/4 (x kg) = x kg

<u>Step 2: </u>

3/4 (1 + x) = x

1 + x = 4x/3

1 = x (4/3 - 1)

x = 1 / (1/3)

x = 3

Weight of Object is 3 kg.

<u>Step 3: </u>

Let's check if this value satisfies the first equation.

3/4 + 3/4 x 3 = 3/4 + 9/4 = 12/4 = 3

Hence proved.

8 0
3 years ago
The expression 9x2 - 5x - 7 has ___ terms and a constant of ___.
elena55 [62]
Answer: first option 3, - 7

Justification:

1) Given expression:9x² - 5x - 7

2) Each monomial is a term.

The monomials are each  combination of numbers and letters (coefficient, letters and exponents) separated of other monomials (terms) with a + or - operator.

3) Therefore, there are 3 terms which are:

9x²,
-5x, and
-7.

The polynomials with 3 terms are called monomials.

4) The monomial (term) withoud letter is the constant. In this case that is  -7.
4 0
4 years ago
Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul
natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

\bf B=\displaystyle\frac{L}{4\pi d^2}

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of  Alpha Centauri A is

\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728

According to the inverse square law for light intensity

\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}

where

\bf I_1= light intensity at distance \bf d_1  

\bf I_2= light intensity at distance \bf d_2  

Let \bf d_2  be the distance we would have to place the 50-watt bulb, then replacing in the formula

\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0
3 years ago
Quadrilateral ABCD was dilated with the origin as the center of dilation to create quadrilateral EFGH on the graph below.
Marianna [84]

Answer:

(x,y)(0.4x, 0.4y) is the answer for your question

3 0
3 years ago
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