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2 years ago

7 added to the product of 14 and f

1 answer:

4 0

14f + 7

“Product” means multiplication, so we can assume 14 and f are being multiplied (14f.) Add that to 7, and you have an expression! Have a great day.

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Given below is the even-number function. Which of the following are equal to E(8)? ALL THAT APPLY PLEASE THERE ARE MULTIPLE RIGH

PIT_PIT [208]

E(8) is the eighth even number as well as 16.

6 0

3 years ago

An exponential relationship has a growth factor of3and y-intercept of 4.Evalute the function that represents the function that r

Murrr4er [49]

Answer:

$f(10)= 236196$

Step-by-step explanation:

Given

$(x,y) = (0,4)$ --- y intercept

$b = 3$ --- growth factor

Required

$f(10)$

An exponential function is represented as:

$y = ab^x$

$(x,y) = (0,4)$ means

$4=a * b^0$

$4=a *1$

$a= 4$

So, we have:

$y = ab^x$

$y = 4(3)^x$

$f(x)= 4(3)^x$

When x is 10, the value of the function is:

$f(x)= 4(3)^x$

$f(10)= 4(3)^{10$

$f(10)= 236196$

6 0

2 years ago

John went on a bike ride to the store 4 miles away. If it took John 310 of an hour to get there and 12 of an hour to get back, w

Kaylis [27]

Answer:

/???

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The diameter of the circle is 12m find the circumference and leave at pi

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

Here, d=12 m

r=12/2=6 m

Now,

Circumference(c)=2πr

=2π6

=12π m

5 0

2 years ago

Evaluate the surface integral. s (x + y + z) ds, s is the parallelogram with parametric equations x = u + v, y = u − v, z = 1 +

Stolb23 [73]

$S$ is given to be parameterized by

$\mathbf r(u,v)=\langle x(u,v),y(u,v),z(u,v)\rangle=\langle u+v,u-v,1+2u+v\rangle$

with $0\le u\le3$ and $0\le v\le2$ . We have

$\mathbf r_u=\langle1,1,2\rangle$
$\mathbf r_v=\langle1,-1,1\rangle$
$\mathbf r_u\times\mathbf r_v=\langle3,1,-2\rangle$
$\left\|\mathbf r_u\times\mathbf r_v\right\|=\sqrt{14}$

The surface integral is then

$\displaystyle\iint_S(x+y+z)\,\mathrm dS=\iint_S(x(u,v)+y(u,v)+z(u,v))\left\|\mathbf r_u\times\mathbf r_v\right\|\,\mathrm du\,\mathrm dv$
$=\displaystyle\sqrt{14}\int_{u=0}^{u=3}\int_{v=0}^{v=2}((u+v)+(u-v)+(1+2u+v))\,\mathrm dv\,\mathrm du$
$=\displaystyle\sqrt{14}\int_{u=0}^{u=3}\int_{v=0}^{v=2}(4u+v+1)\,\mathrm dv\,\mathrm du$
$=\displaystyle\sqrt{14}\left(8\int_{u=0}^{u=3}u\,\mathrm du+3\int_{v=0}^{v=2}v\,\mathrm dv+6\right)$
$=\displaystyle\sqrt{14}\left(8\int_{u=0}^{u=3}u\,\mathrm du+3\int_{v=0}^{v=2}v\,\mathrm dv+6\right)$
$=48\sqrt{14}$

4 0

3 years ago