The correct answer is option B
Are you trying to solve for x and y?
y=2x+1; x+2y=17
sub in one variable in the other equation.
x+2(2x+1)=17
x+4x+2=17
5x=15
x=3
now that you have x value, plug into the original equation to find y and check with the other.
y=2(3)+1 = 7
x+2y=17 = 3 + 2(7) = 17 ; 17=17
Answer:
DE = 18
Step-by-step explanation:
Given that,
Point D is on line segment CE.
DE = x+10, CD=6 and CE=3x
We need to find the length of DE.
ATQ,
CE = CD + DE
Putting all the values,
3x = 6 + x+10
Taking like terms together
3x-x = 16
2x = 16
x = 8
DE = x+10
= 8+10
= 18
Hence, the length of DE is 18.
Answer:
Step-by-step explanation:
The Pythagorean theorem is sqrt(a^2 + b^ 2) = c, so:
sqrt(22^2 + 8^2) = c
sqrt(548) = c
23.41 = c
