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Verizon [17]
3 years ago
10

What would you use a positive and negative number line for?

Mathematics
1 answer:
AysviL [449]3 years ago
7 0
An integer line which represent both positive and negative numbers
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Write 7x = 2401 as a logarithmic function.
Mademuasel [1]

logx2401 = 7

log72401 = x

log24017 = x

logx7 = 2401

5 0
3 years ago
What is the Mean,Mode and range of the set below?:
Zepler [3.9K]

Answer:

Set of numbers: 5, 6, 8, 10, 11, 15, 17, 25, 29, 29, 41, 50, 51, 52, 52, 54, 56, 57, 57

Mean: 32.89

Median: 29

Mode: 29, 52, 57

Range: 52

Step-by-step explanation:

The numbers are already ordered for us, so to find the mean, we need to add the numbers and divide the sum by the number of numbers. This gives us about 32.89.

The median is the middle number in the set, so right in the middle of the set is  29.

The range is the biggest number minus the smallest number, which would be 57-5 = 52.

Mode is the value or values in the data set that occur most frequently, which would be 29, 52, and 57, because they all occur the same number of times.

Happy learning and sorry for the late answer!

--Applepi101

7 0
2 years ago
Read 2 more answers
Fill in the table using this function rule.<br> y = 10x-3<br> X<br> -<br> 0
dexar [7]

Answer:

Step-by-step explanation:

<em>y</em> = 10(- 1) - 3 = <em>- 13</em>

<em>y</em> = 10(0) - 3 = <em>- 3 </em>

<em>y</em> = 10(1)  - 3 =<em> 7 </em>

<em>y</em> = 10(5) - 3 = <em>47</em>

5 0
3 years ago
Evaluate the iterated integral. $$ \int\limits_0^{2\pi}\int\limits_0^y\int\limits_0^x {\color{red}9} \cos(x+y+z)\,dz\,dx\,dy $$
KengaRu [80]
\displaystyle\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\int_{z=0}^{z=x}\cos(x+y+z)\,\mathrm dz\,\mathrm dx\,\mathrm dy=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(x+y+z)\bigg|_{z=0}^{z=x}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(2x+y)-\sin(x+y)\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left(\cos(2x+y)-2\cos(x+y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left((\cos3y-2\cos2y)-(\cos y-2\cos y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dy
\displaystyle=-\frac12\int_{y=0}^{y=2\pi}(\cos3y-2\cos2y+\cos y)\,\mathrm dy
\displaystyle=-\frac12\left(\frac13\sin3y-\sin2y+\sin y\right)\bigg|_{y=0}^{y=2\pi}
=0
4 0
3 years ago
Reabilwe is conducting an experiment in which the temperature is measured carefully. The temperature was 106°C at the end of the
frosja888 [35]

The formula to calculate the temperature (T) after m minutes is -

T = 106 - 6m

We have Reabilwe who is conducting an experiment in which the temperature is measured carefully. The temperature was 106°C at the end of the first minute, and then it falls by 6°C every minute after that.

We have to tp determine a formula to calculate the temperature (T) after m minutes.

<h3 /><h3>Starting from x, if the bacteria count rises by 5 every second, then determine the formula to calculate the bacteria count after 30 seconds.</h3>

Initial count = x

Count increasing per second = 5

Assume that the bacteria count after t seconds is y. Then -

y = x + 5t

for t = 30 ↔ y = 150 + x

According to question, we have -

Initial Temperature = 106 degrees Celsius

Temperature increase per minute = 6 degrees Celsius

Assume that the Temperature fall after m minutes is T. Then -

T = 106 - 6m

Hence, formula to calculate the temperature (T) after m minutes is -

T = 106 - 6m

To solve more questions on Equation Modelling, visit the link below -

brainly.com/question/20876878

#SPJ1

5 0
2 years ago
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