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3 years ago

11

As an airplane rises. the outside temperature from 3.6F for every 1000 feet of elevation gain. Suppose the outside temperature i

s 75F on the ground when the plane takes off and -51F at cruising altitude. How high is the plane then?

1 answer:

harkovskaia [24]3 years ago

7 0

Answer:

35000 feet

Step-by-step explanation:

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4 years ago

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swat32

Answer:

$\left(x^{2-8}\right)+\left(-2x^2\right)=\frac{1}{x^6}-2x^2$

Step-by-step explanation:

$\left(x^{2-8}\right)+\left(-2x^2\right)$

$=x^{2-8}-2x^2$

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3 years ago

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Answer:

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Step-by-step explanation:

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1. Age

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Answer:

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Step-by-step explanation:

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